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julia-pushkina [17]
3 years ago
13

Write down the dissolution equation for rubidium chromate dissolving in water. (Chromate is a polyatomic ion with the formula Cr

O42-.) If two moles of the ionic compound are dissolved, then how many moles of the CATION are present in the solution?
Chemistry
1 answer:
ycow [4]3 years ago
5 0

Answer:

Four moles of the cation

Explanation:

2Rb2CrO4(s)<--------> 4Rb^+(aq) + 2CrO4^2-(aq)

Now looking at the reaction equation, it can be seen that one mole of rubidium chromate contains two moles of rubidium ions and one mole of chromate ions.

The dissolution of two moles of rubidium chromate should then yield four moles of rubidium ions and two moles of chromate ions since the ratio of ions present is 2:1.

This explains the reaction equation written above for the dissolution of two moles of rubidium chromate as shown.

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Citrus2011 [14]
Hello!

Saturated hydrocarbons are generally unreactive except in the presence of high temperatures and oxygen.

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6 0
3 years ago
Remember to balance the equations first
Semenov [28]

mol CO₂ = 9.6

mol N₂ = 4.8

mol O₂ = 0.8

mol H₂O = 8

<h3>Further explanation</h3>

Reaction

4C₃H₅O₉N₃ → 12CO₂ + 6N₂ + O₂ + 10H₂O

mol CO₂

\tt \dfrac{12}{4}\times 3.2=9.6

mol N₂

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mol O₂

\tt \dfrac{1}{4}\times 3.2=0.8

mol H₂O

\tt \dfrac{10}{4}\times 3.2=8

8 0
3 years ago
Explain how you would make 500ml of a 0.100 m naoh solution
icang [17]
Molar mass NaOH =23+16+1=40 g/mol
<span> 0.100 M= 0.100 mol/L
</span>500 ml=0.500 L
0.500L*0.100 mol/L=0.0500 mol NaOH we need to prepare 500 ml solution
0.0500 mol NaOH*40g/1mol=2 g NaOH we need to prepare 500 ml solution
we need  2 g NaOH, dissolve it in small amount of water, and dilute it with water up to 500 mL
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Answer:

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A liquid is heated until boils.
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C. The thermometer reads 100
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