<span>Glycolysis
4 made - 2 used= 2 ATP substrate level
2 NADH x 2= <span>4 ATP </span>(enters at complex II)
Pyruvate Decarboxylation
1 NADH x two pyruvate= 2 NADH x 3= 6 ATP
Krebs Cycle
3 NADH x two pyruvate= 6 x 3= 18 ATP
1 GTP x two pyruvate= 2 GTP= 2 ATP
1 FADH2 x two pyruvate= 2 FADH2 x2= 4 ATP
Total: 2+4+6+18+2+4= 36 ATP</span>
Dont worry those are just variables. a. and b. is the same as 1 and 2 !
Answer:
No
Explanation:
Both A alleles and B alleles are dominant over the O alleles. This means that both parents must have an O allele present to even have a chance of having a child with type O blood. Lets say the mother has type O blood with the father having type AB blood. The possible combination would be: AO, BO, AO, BO. The punnett square should look like this:
A B
O AO BO
O AO BO
