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jasenka [17]
3 years ago
6

Write two numbers, neither of which are 8, they have a GCF of 8

Mathematics
1 answer:
Temka [501]3 years ago
7 0

Answer:

16, 24

Step-by-step explanation:

1 List the factors of each number.

Factors of 16 : 1, 2, 4, 8, 16

Factors of 24 : 1, 2, 3, 4, 6, 8, 12, 24

2 Find the largest number that is shared by all rows above. This is the GCF.

GCF = 8

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mylen [45]
What do u mean like 82+82?
4 0
3 years ago
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A cube has a volume of 343 cubic cm. What is the area of the base
Amanda [17]

Answer:

49 cm²

Step-by-step explanation:

The volume (V) of a cube is calculated as

V = s³ ← s is the length of the side, thus

s³ = 343 ( take the cube root of both sides )

s = \sqrt[3]{343} = 7, thus

area of base = s² = 7² = 49 cm²

6 0
3 years ago
6. Find LCM (10,14,63).​
Katen [24]

Answer:

630 is the LCM

Step-by-step explanation:

You have to list all the multiples of each number till you find the lowest same value one which in this case it's 630.

Multiples of 10:

10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130, 140, 150, 160, 170, 180, 190, 200, 210, 220, 230, 240, 250, 260, 270, 280, 290, 300, 310, 320, 330, 340, 350, 360, 370, 380, 390, 400, 410, 420, 430, 440, 450, 460, 470, 480, 490, 500, 510, 520, 530, 540, 550, 560, 570, 580, 590, 600, 610, 620,<em> 630</em>, 640, 650

Multiples of 14:

14, 28, 42, 56, 70, 84, 98, 112, 126, 140, 154, 168, 182, 196, 210, 224, 238, 252, 266, 280, 294, 308, 322, 336, 350, 364, 378, 392, 406, 420, 434, 448, 462, 476, 490, 504, 518, 532, 546, 560, 574, 588, 602, 616, <em>630</em>, 644, 658

Multiples of 63:

63, 126, 189, 252, 315, 378, 441, 504, 567, <em>630</em>, 693, 756

3 0
3 years ago
The total source voltage in the circuit is 6-3i V. What is the voltage at the middle source
Bezzdna [24]

Answer:

<em>The voltage at the middle source is</em> (2-4\mathbf{i})\ V

Step-by-step explanation:

<u>Voltage Sources in Series</u>

When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.

The figure shown has three voltage sources of values:

2 + 6\mathbf{i}

a + b\mathbf{i}

2 - 5\mathbf{i}

The sum of these voltages is:

V_t=4+a+(6+b-5)\mathbf{i}

Operating:

V_t=4+a+(1+b)\mathbf{i}

We know the total voltage is 6-3\mathbf{i}, thus:

4+a+(1+b)\mathbf{i}=6-3\mathbf{i}

Equating the real parts and the imaginary parts independently:

4+a=6

1+b=-3

Solving each equation:

a = 2

b = -4

The voltage at the middle source is (2-4\mathbf{i})\ V

5 0
2 years ago
Find the perimeter of the following polygon. Be sure to include the correct unit in your answer.
tino4ka555 [31]
The answer is 69.70in
7 0
3 years ago
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