Write two numbers, neither of which are 8, they have a GCF of 8
1 answer:
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Answer:
-8
Step-by-step explanation:
p(x) = - 2x - 3, x ≤ 0 You would use this equation for finding p(0), since 0 is equal to 0.
p(x) = - 2x - 3, x ≤ 0 ← You can ignore the x≤0 part.
p(0) = - 2(0) - 3 Input the value 0 as x.
p(0) = 0 - 3 Simplify
p(0) = -3
Next,
p(x) = -x² - 4, x > 0 You would use this equation for finding p(1), since 1 is greater than 0.
p(x) = -x² - 4, x > 0 ← You can ignore the x>0 part.
p(1) = -(1)² - 4 Input the value 1 as x. 1² is equal to 1 times negative is -1.
p(1) = -1 - 4 Simplify
p(1) = -5
Then,
p(x) = - 2x - 3, x ≤ 0 You would use this equation for finding p(-2), since -2 is less than 0.
p(x) = - 2x - 3, x ≤ 0 ← You can ignore the x ≤ 0 part.
p(-2) = - 2(-2) - 3 Input the value -2 as x. A negative times a negative is
p(-2) = 4 - 3 a positive.
p(-2) = 1 Simplify
Finally, you have to fine the value of
Input the values of p(0), p(1), and p(-2).
Simplify
-8
The answer is -8.