Answer:
38.0 g C2F3Cl3) / (187.3756 g C2F3Cl3/mol) x (3 mol Cl / 1 mol C2F3Cl3) x (35.4532 g Cl/mol) =
21.6 g Cl in C2F3Cl3
When winds move air masses, they carry their weather conditions (heat or cold, dry or moist) from the source region to a new region. When the air mass reaches a new region, it might clash with another air mass that has a different temperature and humidity. This can create a severe storm.
Answer:
50%
Explanation:
You would have to do 15 divided by 30 x 100 to get 50
Percentage Yield = Actual Yield divided by Theoretical Yield
Hope this is right and helpful
Answer:
The answer is B. the hydrophilic end has the hydrocarbon chain.
Explanation:
That answer is wrong because soap and detergent form a bilayer with hydrophilic and hydrophobic ends.
the hydrophilic end interacts with polar compound such as water because that end is ionic and charged, it is composed of carbon and Oxygen and forms dipole interaction and electrostatic interactions.
the hydrophobic end is the non polar end, it is composed of carbon and hydrogen chain (Hydrocarbon) which are non-polar due to equal electronegativity between carbon and hydrogen.
that is why answer B is not true, the hydrophilic end does not have the hydrocarbon chain, the hydrocarbon chain is on the hydrophobic end.
Hund's rule tells us that 1) any orbital in a given subshell must first be occupied by a single electron before being occupied by a second electron and 2) the electrons in a singly occupied orbital all have the same spin.
Diagram I follows both 1 and 2; there are no prematurely-filled orbitals (boxes), and all the singly-filled 2p orbital have the same spin (the arrows are all pointing up). So, diagram I follows Hund's rule and is correct.
Diagram II violates 1: the first box in the 2p subshell is <em>doubly filled </em>while there's still a vacant orbital. That second electron in the first box should be in the third box and pointing upward for diagram II to be correct. Thus, diagram II violates Hund's rule and is incorrect.
Diagram III follows rule 1 but violates rule 2: While every 2p orbital is singly filled, they do <em>not </em>all have the same spin. In the second box, the arrow is pointing down while the arrows in the other two boxes are pointing up. Thus, diagram III violates Hund's rule and is incorrect.
So, of the diagrams given, II and III do not follow Hund's rule and thus are incorrect.
