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barxatty [35]
3 years ago
13

I need this asap!! helppppp

Chemistry
1 answer:
Natasha_Volkova [10]3 years ago
7 0

Hund's rule tells us that 1) any orbital in a given subshell must first be occupied by a single electron before being occupied by a second electron and 2) the electrons in a singly occupied orbital all have the same spin.

Diagram I follows both 1 and 2; there are no prematurely-filled orbitals (boxes), and all the singly-filled 2p orbital have the same spin (the arrows are all pointing up). So, diagram I follows Hund's rule and is correct.

Diagram II violates 1: the first box in the 2p subshell is <em>doubly filled </em>while there's still a vacant orbital. That second electron in the first box should be in the third box and pointing upward for diagram II to be correct. Thus, diagram II violates Hund's rule and is incorrect.

Diagram III follows rule 1 but violates rule 2: While every 2p orbital is singly filled, they do <em>not </em>all have the same spin. In the second box, the arrow is pointing down while the arrows in the other two boxes are pointing up. Thus, diagram III violates Hund's rule and is incorrect.

So, of the diagrams given, II and III do not follow Hund's rule and thus are incorrect.    

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3 years ago
Please help!! due so soon!!!!
Leokris [45]

Answer:

hey, i hope this helps

Explanation:

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6 0
2 years ago
Which of the following scientists was awarded the Nobel Prize in
vlabodo [156]

z) Marie Curie

Explanation:

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Learn more:

Transmutation brainly.com/question/3433940

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3 0
3 years ago
Hello I need help very bad!!!
Oksanka [162]

D. Cell membrane: surrounds a cell and allows substances to pass in and out

6 0
3 years ago
Under what pressure will a scientist need to store 0.400 miles of gas if the container has a volume of 200.0 mL and the temperat
mihalych1998 [28]
Hello!

Ok so for this problem we use the ideal gas law of PV=nRT and I take it that the scientist needs to store 0.400 moles of gas and not miles.

So if we have
n=0.400mol
V=0.200L
T= 23degC= 273k+23c=296k
R=ideal gas constant= 0.0821 L*atm/mol*k

So now we rearrange equation for pressure(P)

P=nRT/V
P=((0.400mol)*(0.0821 L*atm/mol*k)*(296k))/(0.200L) = 48.6 atm of pressure

Hope this helps you understand the concept and how to solve yourself in the future!! Any questions, please feel free to ask!! Thank you kindly!!!
4 0
3 years ago
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