How much heat do you need to raise the temperature of 150 g of ice from -30°C to -15°c?

1 answer:

4 0

To solve this question, you must use the formula: q=mc(change in temperature), where q is heat, m is mass, C is specific heat and temperature change is temperature change. The specific heat for ice is 2.1kJ/Kg x K (given). The change in temperature is 15 degrees Celsius (which you should change to kelvins so you can cancel out units), or 273 + 15 = 288K. The mass is 150 grams, which is 0.15 kg. Now, we can solve for q, heat. We will do this by substituting variables into the formula. After simplifying and cancelling out units, the answer we get is: 90.72kJ.

You might be interested in

A reaction mixture, in an organic solvent, contains an organic acid, an organic base, neutral organic compounds, and base contai

zheka24 [161]

Answer: option b. Neutral organic compounds

Explanation:

3 0

2 years ago

How to write generic word equation and a chemical equation for the reaction that occurs when an anhydrous salt is placed in wate

Oksana_A [137]

The generic solution of the reaction that occurs would be writen as water + anhydrous salt = hydrated salt
chemical equation would look like this xH2O +AB = AB.xH2O

3 0

2 years ago

What is of or from outside of the earth

WINSTONCH [101]

Answer The outer layer of the Earth is called the crust.

Explanation: Because it's in the earth atmosphere

4 0

2 years ago

Balanced chemical equation: BaCl2(aq)+Na2SO4(aq)⟶BaSO4(s)+2NaCl(aq)

Ipatiy [6.2K]

Answer:

Part 1) 85.3 grams NaCl

Part 2) 8.79 x 10²³ formula units NaCl

Explanation:

To find the mass of NaCl, you need to multiply the given value (1.46 moles) by the molar mass of NaCl. This measurement is the atomic masses of the elements times each of their quantities combined. In this case, there is only one mole of each element in the molecule. Moles should be located in the denominator of the conversion to allow for the cancellation of units. The final answer should have 3 sig figs to reflect the given value.

Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol
Molar Mass (NaCl): 58.44 g/mol

1.46 moles NaCl 58.44 g
--------------------------- x ---------------- = 85.3 grams NaCl
1 mole

I do not know which other question the second part is referring to, so I will just use the moles given in the first part. To find the formula units, you need to multiply the given value (1.46 moles NaCl) by Avogadro's Number. This conversion represents the number of formula units found in 1 mole of the sample. The moles should be in the denominator of the conversion to allow for the cancellation of units.

Avogadro's Number:

1 mole = 6.022 x 10²³ formula units

1.46 moles NaCl 6.022 x 10²³ units
------------------------ x ----------------------------- = 8.79 x 10²³ formula units NaCl
1 mole

4 0

1 year ago

Make an observation about the average height of the beanbag for each mass dropped. How does it compare with your calculated kine

Gekata [30.6K]

Answer:

the other person is correct

Explanation:

3 0

2 years ago