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Dimas [21]
3 years ago
8

How does the density of air affect local weather patterns?

Chemistry
1 answer:
JulijaS [17]3 years ago
5 0
When winds move air masses, they carry their weather conditions (heat or cold, dry or moist) from the source region to a new region. When the air mass reaches a new region, it might clash with another air mass that has a different temperature and humidity. This can create a severe storm.
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2FeCl3 + MgO -&gt; Fe2O3 + 3MgCl2<br> Convert 3.00 moles of MgO to moles of Fe2O3
nikitadnepr [17]

71.8 g of iron (III) oxide (Fe₂O₃) were produced from 3 moles of magnesium oxide (MgO).

Explanation:

We have the following chemical reaction:

2 FeCl₃ + 3 MgO → Fe₂O₃ + 3 MgCl₂

We see from the chemical reaction that 3 moles of magnesium oxide (MgO) will produce 1 mole of iron (III) oxide (Fe₂O₃).

number of moles = mass / molar weight

mass = number of moles × molar weight

mass of Fe₂O₃ = 1 × 71.8 = 71.8 g

Learn more about:

number of moles

brainly.com/question/13981579

#learnwithBrainly

6 0
3 years ago
Where do glaciers come from
marusya05 [52]

Answer:GLACIERS  ARE MADE UP OF  FALLEN SNOW OVER MILLION YEARS, IN MOST OF POLAR REGIONS  IT TURNS TO ICE AND WILL FLOW DOWNWARDS AND OUTWARDS UNDER ITS OWN PRESSURE

AND THE LARGEST GLACIER IN THE WORLD IS 60 MILES WIDE AND AROUND  270 MILES LONG.

IT COVERS 10% OF EARTH'S TOTAL LAND

Explanation:

4 0
4 years ago
An unknown compound has the following chemical formula:
luda_lava [24]

Answer:

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Explanation:

4 0
3 years ago
You have 363 mL of a 1.25M potassium chloride solution, but you need to make a 0.50M potassium chloride solution. How many milli
maxonik [38]

Answer:- 544.5 mL of water need to be added.

Solution:- It is a dilution problem. The equation used for solving this type of problems is:

M_1V_1=M_2V_2

where, M_1 is initial molarity and  M_2 is the molarity after dilution. Similarly,  V_1 is the volume before dilution and  V_2 is the volume after dilution.

Let's plug in the values in the equation:

1.25M(363mL)=0.50M(V_2)

V_2=\frac{1.25M(363mL)}{0.50M}

V_2=907.5mL

Volume of water added = 907.5mL - 363mL  = 544.5 mL

So, 544.5 mL of water are need to be added to the original solution for dilution.

3 0
3 years ago
How many gallons in 1.3 liter for gas tank?
Veseljchak [2.6K]

0.34342367

hopes this helps,

Xeno

6 0
3 years ago
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