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IRINA_888 [86]
3 years ago
8

Inez and Joel work at a store that sells

Mathematics
2 answers:
dmitriy555 [2]3 years ago
8 0

Answer:

2 hours 32 minutes

Step-by-step explanation:

Subtract.

If you could subscribe to my friend penny_pg3d on YT, that would be great! :)

Anvisha [2.4K]3 years ago
4 0
2 hours 32 minutes
This is the answer I got so the first guy got it right
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PLZ HELP ITS ALL MY POINTS
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30 cm

Step-by-step explanation:

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I need help Asap! i will be putting brainliest
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I THINK ITS THE 3rd on

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How many solutions does the equation −3x−17=−17−3x have?
harkovskaia [24]

Answer:

an infinite number of solutions

Step-by-step explanation:

−3x −17 = −17 −3x

left side = right side  TRUE because -3x-17 is the same as -17-3x

we can rearrange  the the equation

−3x −17 +17 = −17 +17−3x, add 17 on both sides of the equations

            -3x = -3x, divide both sides by (-3)

               x = x

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3 years ago
At Brunswick Elementary school, 2/5 of six-grade students have at least one pet. If school has 181 sixth graders, about how many
VashaNatasha [74]

Answer: 72.4

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6 0
2 years ago
One fifth of a number plus three times the number is equal to twice the number plus 42. What is the number
borishaifa [10]

Equation to find number's value: \frac{1}{5}n + 3n = 2n + 42

Number's value: n = 35


Explanation:

Let n be the unknown number for this problem.

One fifth of a number is the same as \frac{1}{5}n.

Three times the number is the same as 3n.

Twice the number plus 42 is the same as 2n + 42.

So, using the information we've gathered so far, we can create the equation that will provide us with n's value.

Equation: \frac{1}{5}n + 3n = 2n + 42

We can use this equation to find n's value.

You can subtract 2n from both sides to get the equation \frac{1}{5}n + n = 42, which is the same thing as the equation we were using.

Now add n and \frac{1}{5}n together to get 1\frac{1}{5}n.

After you do this, your equation should look like 1\frac{1}{5}n=42.

Now divide both sides by 1\frac{1}{5} to get n's value.

n = 35

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3 years ago
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