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guapka [62]
4 years ago
8

Answer the following questions for projectile motion on level ground assuming negligible air resistance (the initial angle being

neither 0° nor 90° ): (a) Is the velocity ever zero? (b) When is the velocity a minimum? A maximum? (c) Can the velocity ever be the same as the initial velocity at a time other than at t = 0? (d) Can the speed ever be the same as the initial speed at a time other than at t = 0?
Physics
1 answer:
Paha777 [63]4 years ago
8 0

(a) Is the velocity ever zero?

Answer:

NO, it will never become zero

Explanation:

Since velocity is constant always along x direction as there is no acceleration in that direction so its velocity in x direction always remains same and net velocity is never zero during motion.

(b) When is the velocity a minimum? A maximum?

Answer:

Velocity is minimum when it will reach the maximum height.

Velocity is maximum when it will reach the ground back or initial velocity is maximum

Explanation:

Since we know that y component of velocity will become zero at its maximum height

So here we can say that velocity is minimum when it will reach the top point of its path.

Since during its upward motion it is moving against gravity so here its vertical component of velocity will decrease with time

So maximum velocity is either initial velocity of the velocity when it will hit the ground again

(c) Can the velocity ever be the same as the initial velocity at a time other than at t = 0?

Answer:

No, it will never equal to its initial velocity

Explanation:

It is never equal to initial velocity because here its direction of motion will change with time and since velocity is a vector quantity so here its direction never equal to initial velocity.

(d) Can the speed ever be the same as the initial speed at a time other than at t = 0?

Answer:

Yes speed will be same when it will hit the ground again

Explanation:

Since we know by energy conservation law that here no frictional force acts on the object so energy will be same when it will hit the floor so here its speed will be equal to initial speed

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A 4.50-kg wheel that is 34.5 cm in diametet rotates through an angle of 13.8 rad as it slows down uniformly from 22.0 rad/s to 1
lisabon 2012 [21]

Answer:

\alpha =10.93radian/sec^2

Explanation:

We have given given the final angular velocity \omega _{final}=13.5rad/sec

And \omega _{initial}=22rad/sec

Displacement \Theta =13.8radian

We have to find the angular acceleration \alpha

According to law of motion \omega _{final}^2=\omega _{initial}^2+2\alpha \Theta

So 13.5^2=22^2+2\times \alpha \times 13.8

\alpha =-10.93radian/sec^2

In question we have tell about magnitude only so \alpha =10.93radian/sec^2

4 0
3 years ago
Jim is driving a 2268-kg pickup truck at 19 m/s and releases his foot from the accelerator pedal. The car eventually stops due t
lord [1]

Answer:

The initial kinetic energy of the truck is 409374 J

Explanation:

This problem can be solved in two ways. Let´s solve it first in the easiest way.

The kinetic energy is calculated using this equation:

E = 1/2 · m · v²

Where:

E = kinetic energy

m = mass

v = velocity

Then, the kinetic energy of the truck will be:

E = 1/2 · 2268 kg · (19 m/s)² = 409374 J

And that´s it.

But we can complicate it a bit:

The kinetic energy is the work needed to move an object from rest to a desired velocity. If the object is moving, the work needed to stop it must be of the same magnitude as its kinetic energy (in the opposite direction to the movement).

The equation for work is:

W = F · d

Where:

W= work

F = force

d = distance

We know the magnitude of the force applied to the truck, but we do not know for how much distance that force was applied. The distance can be calculated using the equation for the position of an object moving in a straight line:

x = x0 + v0 · t + 1/2 · a · t²

where

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

But we still do not know the time nor the acceleration.

The acceleration can be obtained from the equation of force:

F = m · a

Where

F = force

m = mass

a = acceleration

Then:

900 N = 2268 kg ·a

a = 900 N /2268 kg = 0.397 m/s²

Now, we can calculate the time needed for the truck to stop. We know that at the final time, the velocity is 0. Then, we can use the equation for velocity to obtain that time:

v = v0 + a · t

Where:

v = velocity at time t

v0 = initial velocity

a = acceleration

t = time

Then:

v = 19 m/s - 0.397 m/s² · t

0 = 19 m/s - 0.397 m/s² · t

-19 m/s / -0.397 m/s² = t (acceleration is negative because it is opposite to the direction of the movement)

t = 47.86 s (The truck stoped at 47.86 s after releasing the foot from the accelerator pedal)

With the time and acceleration, we can calculate the traveled distance.

x = 0 m + 19 m/s · 47.86 s - 1/2 · 0.397 m/s² · (47.86s)²

x = 454.66 m (without rounding the acceleration nor the time, the value will be 454.86 m)

Now, we can calculate the work done to stop the truck which will be of the same magnitude as the kinetic energy:

W = 900 N · 454.66 m = 409194 J

(if you do all the calculations without rounding, you will get the same value as we calculated above using the equation of kinetic energy, 409374 J).

3 0
3 years ago
How does rocks and fossils determine Earth's age?
liq [111]

Answer:

There are two main ways to determine the age of a rock, these are Relative dating and Absolute dating. Relative dating is used to determine the relative order of past events by comparing the age of one object to another.

Explanation:

6 0
3 years ago
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A small box slides down a ramp on a friction with surface. If the total energy of the system is conserved, which computational m
spayn [35]

Answer:

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Explanation:

6 0
3 years ago
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How do you calculate the mass of an object accelerating at22.35m/s2 with a force of 120N
Arte-miy333 [17]

Answer:

The mass of object is calculated as 5.36 kg

Explanation:

The known terms to find the mass are:

           acceleration of object (a) = 22.35 m/s^{2}

                        Force exerted (F) = 120N

                        mass of an object (m) = ?

From Newton's second law of motion;

                                   F = ma

                           or, 120 = m × 22.35

                          or, m= \frac{120}{22.35} kg

                           ∴ m = 5.36 kg

3 0
3 years ago
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