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3 years ago

How many grams are 3.01 × 1023 molecules of CuSO4?

1 answer:

4 0

Answer is: 79.8 grams of copper(II) sulfate.
N(CuSO₄) = 3.01·10²³; number of molecules.
n(CuSO₄) = N(CuSO₄) ÷ Na.
n(CuSO₄) = 3.01·10²³ ÷ 6.02·10²³ 1/mol.
n(CuSO₄) = 0.5 mol; amount of substance.
m(CuSO₄) = n(CuSO₄) · M(CuSO₄).
m(CuSO₄) = 0.5 mol · 159.6 g/mol.
m(CuSO₄) = 79.8 g; mass of substance.
M - molar mass.

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Since this reaction takes place in acidic solution, H2O(l) and H+(aq) will be involved in the reaction. Places for these species

maxonik [38]

Answer:

The balanced equation is given below:

SO4^2−(aq)+ Sn^2+(aq) + 4H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

The coefficients of the reactants are: 1, 1, 4

The coefficients of the products are: 1, 1, 1

Explanation:

Step 1:

The equation for the reaction. This is given below:

SO4^2−(aq)+ Sn^2+(aq) + –––→ H2SO3(aq)+ Sn^4+(aq) + –––

Step 2:

Inclusion of H+ and H2O into the equation. This is illustrated below:

SO4^2−(aq)+ Sn^2+(aq) + H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

Step 3:

Balancing the equation.

SO4^2−(aq)+ Sn^2+(aq) + H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

The above equation can be balanced as follow:

There are total 4 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 4 in front of H^+ as shown below:

SO4^2−(aq)+ Sn^2+(aq) + 4H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

Now the equation is balanced.

The coefficients of the reactants are: 1, 1, 4

The coefficients of the products are: 1, 1, 1

5 0

3 years ago

Ammonium chloride, ammonium sulfate and ammonium nitrate are used in fertilisers.

Hoochie [10]

Answer:

1.0625 g

Explanation:

Number of moles in 5g of NH4NO3 = 5.0g/80g/mol = 0.0625 moles

Again the balanced reaction equation is;

NH3 + HNO3 → NH4NO3

So,

1 mole of NH3 yields 1 mole of NH4NO3

x moles of NH3 yields 0.0625 moles of NH4NO3

x = 0.0625 moles of NH3

Mass of NH3 = number of moles * molar mass

Mass of NH3 = 0.0625 moles * 17g/mol

Mass of NH3 = 1.0625 g

7 0

3 years ago

Find the mass of 3.27 x 10^23 molecules of H2SO4. Use 3 significant digits<br> and put the units.

marta [7]

Answer:

Approximately $53.3\; \rm g$ .

Explanation:

Lookup Avogadro's Number: $N_{\rm A} = 6.02\times 10^{23}\; \rm mol^{-1}$ (three significant figures.)

Lookup the relative atomic mass of $\rm H$ , $\rm S$ , and $\rm O$ on a modern periodic table:

$\rm H$ : $1.008$ .
$\rm S$ : $32.06$ .
$\rm O$ : $15.999$ .

(For example, the relative atomic mass of $\rm H$ is $1.008$ means that the mass of one mole of $\rm H\!$ atoms would be approximately $1.008\!$ grams on average.)

The question counted the number of $\rm H_2SO_4$ molecules without using any unit. Avogadro's Number $N_{\rm A}$ helps convert the unit of that count to moles.

Each mole of $\rm H_2SO_4$ molecules includes exactly $(1\; {\rm mol} \times N_\text{A}) \approx 6.02\times 10^{23}$ of these $\rm H_2SO_4 \!$ molecules.

$3.27 \times 10^{23}$ $\rm H_2SO_4$ molecules would correspond to $\displaystyle n = \frac{N}{N_{\rm A}} \approx \frac{3.27 \times 10^{23}}{6.02 \times 10^{23}\; \rm mol^{-1}} \approx 0.541389\; \rm mol$ of such molecules.

(Keep more significant figures than required during intermediary steps.)

The formula mass of $\rm H_2SO_4$ gives the mass of each mole of $\rm H_2SO_4\!$ molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:

$\begin{aligned}& M({\rm H_2SO_4}) \\ &= (2 \times 1.008 + 32.06 + 4 \times 15.999)\; \rm g \cdot mol^{-1} \\ &= 98.702\; \rm g \cdot mol^{-1}\end{aligned}$ .

Calculate the mass of approximately $0.541389\; \rm mol$ of $\rm H_2SO_4$ :

$\begin{aligned}m &= n \cdot M \\ &\approx 0.541389\; \rm mol \times 98.702\; \rm g \cdot mol^{-1}\\ &\approx 53.3\; \rm g\end{aligned}$ .

(Rounded to three significant figures.)

6 0

3 years ago

What kind of melocule is water?A:nonpolarB:ionicC:polarD:charged

hram777 [196]

The correct answer is:  [C]:  "polar" .
_____________________________________________________
" Water " ; which is: " H₂O " ;
_____________________________________________________
is a:
_____________________________________________________

  — polar; → {eliminate: "Choice [A]: "non-polar"} ;

→ {and consider: "Choice: [C]: "polar" } ;

— covalent; → {not "ionic"; eliminate: "Choice: [B]: "ionic"} ;

— uncharged; → {neutral compound; not "charged" —but "balanced"} ;

→ {Note: " H ⁺ , O ²⁻ ; → " H₂O " } ;

→ The "charges" balance/ cancel out.

→ {eliminate: "Choice: [D]: "charged" .}.
_______________________________________________________
— compound.
_______________________________________________________

The correct answer is: [C]: "polar" .
_______________________________________________________

6 0

4 years ago

15 points <br> Discuss how cells differ from one another

Sladkaya [172]

Answer:

Cellular differentiation is the process in which a cell changes from one cell type to another. Usually, the cell changes to a more specialized type. Differentiation occurs numerous times during the development of a multicellular organism as it changes from a simple zygote to a complex system of tissues and cell types.

Explanation: from google

5 0

3 years ago