Answer:
THE EMPIRICAL FORMULA FOR THE UNKNOWN COMPOUND IS C7H9O
Explanation:
The empirical formula for the unknown compound can be obtained by following the processes below:
1 . Write out the percentage composition of the individual elements in the compound
C = 75.68 %
H = 8.80 %
O = 15.52 %
2. Divide the percentage composition by the atomic masses of the elements
C = 75 .68 / 12 = 6.3066
H = 8.80 / 1 = 8.8000
O = 15.52 / 16 = 0.9700
3. Divide the individual results by the lowest values
C = 6.3066 / 0.9700 = 6.5016
H = 8.8000 / 0.9700 = 9.0722
O = 0.9700 / 0.9700 = 1
4. Round up the values to the whole number
C = 7
H = 9
O = 1
5 Write out the empirical formula for the compound
C7H90
In conclusion, the empirical formula for the unknown compound is therefore C7H9O
Answer:
The coefficient for Al(s) is 2.
Explanation:
__ Al(s) __ O2(g) --> __ Al2O3(s)
__ Al(s) __ O2(g) --> 1 Al2O3(s)
1 Al(s) __ O2(g) --> 1 Al2O3(s)
1 Al(s) + 1.5 O2(g) --> 1 Al2O3(s) [Use a fraction to make it balance]
2 Al(s) + 3 O2(g) --> 2 Al2O3(s) [Convert the 1.5 fraction to a whole number by multiplying all coefficients by 2]
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