Answer: The percent yield of the reaction is 83.5 %
Explanation:
The given balanced equation is
is the limiting reagent as it limits the formation of product and is the excess reagent.
According to stoichiometry :
60.08 g of produce = 40.11 of
Thus 50.0 of will produce= of
Experimental yield of SiC = 27.9 g
Percent yield =
Thus percent yield of the reaction is 83.5 %
Answer:
–2733.4 KJ
Explanation:
The balanced equation for the reaction is given below:
C₂H₅OH + 3O₂ —> 2CO₂ + 3H₂O
ΔH = −1366.7 kJ
From the balanced equation above,
1 mole of C₂H₅OH reacted to produce enthalpy change (ΔH) of −1366.7 kJ.
Finally, we shall determine the enthalpy change (ΔH) produced by the reaction of 2 moles of C₂H₅OH. This can be obtained as follow:
From the balanced equation above,
1 mole of C₂H₅OH reacted to produce enthalpy change (ΔH) of −1366.7 kJ.
Therefore, 2 moles of C₂H₅OH will react to produce enthalpy change (ΔH) of = 2 × −1366.7 = –2733.4 KJ.
Thus, enthalpy change (ΔH) obtained is –2733.4 KJ
Answer:
hope that helps
Explanation:
The total mass of reactants taken = 15.9 + 20.0 = 35.9 gm. From the conservation of mass the final mass of the contents of the vessel should also be 35.9 gm. But it is only 29.3 gm. The difference is due to the mass of released carbon dioxide gas.Hence the mass of carbon dioxide gas released = 35.9 – 29.3 = 6.6 gm