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3 years ago

6

The total of your dinner bill plus tip is 19.00$ You left a 3.00$ tip the 3.00$ tip is what percent of the dinner bill help plzz

z

1 answer:

Norma-Jean [14]3 years ago

7 0

Answer:

About 15%

Step-by-step explanation:

3 divided by 19 is 0.1578947368421053

0.1578947368421053 multiplied by 100 is 15.78947368421053‬.

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ZanzabumX [31]

Answer:

To create function h, function f was translated 2 units right , translated 4 units up and reflected across the x axis

Step-by-step explanation:

Given

$f(x) = x^3$

$h(x) =-(x + 2)^3 - 4$

Required

Complete chart

First: f(x) was translated right by 2 units

The rule of right translation is $(x,y) \to (x + 2,y)$

So, we have:

$f'(x) = f(x + 2)$

$f'(x) = (x + 2)^3$

Next: f'(x) was translated up by 4 units

The rule of down translation is $(x,y) \to (x,y+4)$

So, we have:

$f"(x) = f'(x) +4$

$f"(x) = (x + 2)^3 +4$

Lastly, f"(x) was reflected across the x-axis;

The rule of this reflection is: $(x,y) \to (x,-y)$

So, we have:

$h(x) = -f"(x)$

$h(x) = -[(x+2)^3 + 4]$

Remove bracket

$h(x) = -(x+2)^3 - 4$

8 0

3 years ago

I really need help please<br> Will give you a thanks and make you the brainliest!

kolbaska11 [484]

Answer:

a= 2s +3t

b= -m+4

c= a+2b+c

d= 2x-1

e= x squared + 3x +6

f= 4t-2st-s

3 0

3 years ago

What times 0.6 equals 0.225

seraphim [82]

0.135 Hope this helps :)

5 0

3 years ago

Read 2 more answers

A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and

mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

$\mu = \frac{3X_{1} + 4X_{2} }{8}$

Now

Bias for the estimator = E(μ bar) - μ

= $E( \frac{3X_{1} + 4X_{2} }{8}) - 4.5$

= $\frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5$

= $\frac{3(4.5) + 4(4.5)}{8} - 4.5$

= $\frac{13.5 + 18}{8} - 4.5$

= $\frac{31.5}{8} - 4.5$

= 3.9375 - 4.5

= - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

= Var(μ bar) + [Bias(μ bar, μ)]²

= $Var( \frac{3X_{1} + 4X_{2} }{8}) + 0.3136$

= $\frac{1}{64} Var( {3X_{1} + 4X_{2} }) + 0.3136$

= $\frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})] }) + 0.3136$

= $\frac{1}{64} [{3(57.76) + 4(57.76)}] } + 0.3136$

= $\frac{1}{64} [7(57.76)}] } + 0.3136$

= $\frac{1}{64} [404.32] } + 0.3136$

= $6.3175 + 0.3136$

= 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0

3 years ago

A radio station requires DJs to play 3 commercials for every 18 songs they play. What is the unit rate of songs to commercials?

bulgar [2K]

6 songs

The way to find this answer is to divide 18 by 3, which is six, which means that after every six songs a commercial is played.

Hope this was helpful and that I explained it correctly.

3 0

3 years ago