Answer:
Logan played for 22 minutes during the second half.
Step-by-step explanation:
Since Keith played the first 22 minutes of a soccer game and Logan then replaced him for the rest of the half, and Logan started the second half and was replaced by Wilson with 18 minutes left in the game, if each half is 40 minutes long To determine how long did Logan play during the second half, the following calculation must be performed:
Second Half Total - Time Played by Wilson = Time Played by Logan
40 - 18 = X
22 = X
Therefore, Logan played for 22 minutes during the second half.
Answer:
Step-by-step explanation:
Given
on Sales over 50000
Required
Determine the function j(s) for sales over 50000
Represent the total sales in a month with s.
Sales over 50000 in that month will be: s - 50000
So, the function j(s) is:
j(s) = Base Amount + Commission * Sales over 50000
Convert % to decimal
Open bracket
Collect Like Terms
Answer:
the answer is 4y-2
Step-by-step explanation:
To simplify any algebraic expression you need to add liketerms.
In this equation, the liketerms are y and 3y.
3y+y= 4y
We are left with 4y-2; we cant go any further, because 4y and -2 are not liketerms.
Answer:
The answer to the question are
(B) The set is not a vector space because it is not closed under addition. and
(D) The set is not a vector space because an additive inverse does not exist.
Step-by-step explanation:
To be able to identify the possible things that can affect a possible vector space one would have to practice on several exercises.
The vector space axioms that failed are as follows
(B) The set is not a vector space because it is not closed under addition.
(2·x⁸ + 3·x) + (-2·x⁸ +x) = 4·x which is not an eighth degree polynomial
(D) The set is not a vector space because an additive inverse does not exist.
There is no eight degree polynomial = 0
The axioms for real vector space are
- Addition: Possibility of forming the sum x+y which is in X from elements x and y which are also in X
- Inverse: Possibility of forming an inverse -x which is in X from an element x which is in X
- Scalar multiplication: The possibility of forming multiplication between an element x in X and a real number c of which the product cx is also an element of X
5+ 2n < 1+ 6n , n= number
