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PIT_PIT [208]
2 years ago
7

X=10 3x+5y=20 in the system of equations, what is the value of y

Mathematics
2 answers:
vova2212 [387]2 years ago
6 0
3(10) + 5y = 20
5y = 20 - 30
5y = - 10
y = - 2
Lera25 [3.4K]2 years ago
6 0
You can't get that problem to equal 20, Because 3*10=30 and 30+5 is 35 and if you stop there u can see u went way over 20 and the you're bout to multiply your answer again by y . So this is a treat question.  <span />
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20 POINTS WILL MARK AS BRAINLIEST AND SAY THANKS In 2000, the cost of many items increased because the increase in the cost of g
antoniya [11.8K]
Let the cost of gasoline in the year 2000 be represented b the equation
y = a + b*x
where
x = months, counted from January
y = cost, dollars

The given data in the table is
Month:        Jan  Feb  Mar  Apr  May  Jun  Jul  Aug  Sep  Oct  Nov  Dec
x, months:       1       2     3       4      5       6     7      8      9     10     11      12
y, dollars:     ---      ---     ---     ---   1.76   2.13   ---     ---    ---      ---    ---     ---

When x = 5, y = 1.76.
Therefore
a + 5b = 1.76               (1)

When x = 6, y = 2.13
Therefore
a + 6b = 2.13              (2)

Subtract equation (1) from (2).
a + 6b - (a + 5b) = 2.13 - 1.76
b = 0.37

From (1), obtain
a = 1.76 - 5b
   = 1.76 - 5*0.37
   = -0.09

The required equation is
y = 0.37x - 0.09
The graph shows the line, with the given data for May and June.

Answer: D.  y = 0.37x - 0.09

7 0
3 years ago
Consider the following system of equations:
Delicious77 [7]

Answer:

The system has infinitely solutions

Step-by-step explanation:

we have

-\frac{1}{3}x^{2}=-\frac{5}{6}+\frac{1}{3}y^{2}

\frac{1}{3}x^{2}+\frac{1}{3}y^{2}=\frac{5}{6}

Multiply by 3 both sides

x^{2}+y^{2}=\frac{5}{2} ----> equation A

The equation A is a circle centered at origin with radius r=\sqrt{5/2}\ units

and

5y^{2} =\frac{25}{2}-5x^{2}

5x^{2}+5y^{2} =\frac{25}{2}

Divide by 5 both sides

x^{2}+y^{2} =\frac{5}{2} ----> equation B

The equation B is a circle centered at origin with radius r=\sqrt{5/2}\ units

Equation A and Equation B are the same

Therefore

The system has infinitely solutions

7 0
3 years ago
Read 2 more answers
Which expression has a value of 1/36?
Schach [20]
(1/36) = 0.0277777777778

(1/108)^3 = 7.9383224102<span> x 10^-7 </span>
(1/9)^4 = 0.000152415790276
(1/6)^2 = 0.0277777777778
(1/2)^5 =  <span>0.03125

The only one that matches with the value of 1/36 is (1/6)^2. Therefore, your answer is C. (1/6)^2
</span>




6 0
3 years ago
Read 2 more answers
Solve for x<br> y=7x−7z−9
juin [17]

y=7x−7z−9

7x = y + 7z + 9

 x = y/7 + z + 9/7

5 0
3 years ago
X=y+1400<br> 0.08x+0.05=840
mezya [45]

Answer:

x = 7000

y = 5600

(7000, 5600)

Step-by-step explanation:

To solve the system of equations means to find the point of intersection (graphically). You are finding what value of 'x' and what value of 'y' fits both equations.

x = y + 1400

0.08x + 0.05y = 840

We can solve using the method <u>substitution</u>, where you replace a variable in one equation with an equivalent expression.

<u>Since "x" is y + 1400, we can replace "x" in the second equation.</u>

0.08x + 0.05y = 840

0.08(y + 1400) + 0.05y = 840    

Distribute over brackets by multiplying 0.08 with y, then 0.08 with 1400.

0.08y + 112 + 0.05y = 840         Collect like terms (with "y" variable)

112 + 0.13y = 840

Now isolate "y" in the simplified equation.

112 - 112 + 0.13y = 840 - 112         Subtract 112 from both sides

0.13y = 728

0.13y/0.13 = 728/0.13         Divide both sides by 0.13

y = 5600         Solved for y

We can substitute "y" with 5600 in any other equation that has "x".

x = y + 1400

x = 5600 + 1400          Add

x = 7000         Solved for x

You may express the answer as a coordinate, or an ordered pair (x, y).

The solution is (7000, 5600).

3 0
3 years ago
Read 2 more answers
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