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Oduvanchick [21]
3 years ago
11

The pressure of a scuba tank should be within 500 pounds per square inch (psi)of 2500 psi. Write the range of optimum pressures.

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
3 0

The range would be between 2000 and 3000 PSI.

Explanation:

2500 PSI - 500 PSI = 2000 PSI

2500 PSI + 500 PSI = 3000 PSI

Hope this helps :)

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Anastasy [175]

Answer: 4

you have to find prime factors of each number

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Does the line passing through the points (−1,−5) and (2,1) intersect the line passing through the points (−1,−6) and (1,2)?
Serggg [28]

Answer:

Yes

Step-by-step explanation:

As long as the slopes of these two lines are not the same, they will intersect.

Given two points on a line, we can find the slope by taking the difference in the y coordinates and dividing it by the difference in the x coordinates.

Slope of 1st line: \frac{-5-1}{-1-2} =\frac{-6}{-3} =\frac{1}{2}

Slope of 2nd line: \frac{-6-2}{-1-1} =\frac{-8}{-2}=4

The slopes are not equal, therefore the lines intersect.

5 0
3 years ago
(HELPPPPPP)This graph relates the volumes of triangular pyramids with a base area of 12 square inches and their heights. Volumes
aleksklad [387]

Answer:

b

Step-by-step explanation:

7 0
4 years ago
A bike path is 6 3/4 miles long. what whole number is closest to 6 3/4
Svet_ta [14]
22 will be the whole number
5 0
4 years ago
A sheet of paper 90 cm-by-66 cm is made into an open box (i.e. there's no top), by cutting x-cm squares out of each corner and f
NNADVOKAT [17]

Answer:

26 - \sqrt{181} cm

Step-by-step explanation:

The volume of the box is:

V = height * length * width

V = x*(66 - 2*x)*(90 - 2*x)

V = (66*x - 2*x^2)*(90 - 2*x)

V = 5940*x - 132*x^2 - 180*x^2 + 4*x^3

V = 4*x^3 - 312*x^2 + 5940*x

where x is the length of the sides of the squares,  in cm.

The mathematical problem is :

Maximize: V = 4*x^3 - 312*x^2 + 5940*x

subject to:

x > 0

2*x < 66 <=> x < 33

In the maximum, the first derivative of V, dV/dx, is equal to zero

dV/dx = 12*x^2 - 624*x + 5940

From quadratic formula

x = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}

x = \frac{624 \pm \sqrt{(-624)^2 - 4(12)(5940)}}{2(12)}

x = \frac{624 \pm \sqrt{104256}}{24}

x = \frac{624 \pm \sqrt{2^6*3^2*181}}{24}

x = \frac{624 \pm 8*3*\sqrt{181}}{24}

x_1 = \frac{624 + 24*\sqrt{181}}{24}

x_1 = 26 + \sqrt{181}

x_2 = \frac{624 - 24*\sqrt{181}}{24}

x_2 = 26 - \sqrt{181}

But x_1 > 33, then is not the correct answer.

5 0
3 years ago
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