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grigory [225]
3 years ago
12

A) 2.5x + 1.25 < 3.75 b)5.12 2.4x + 0.3help!!!​

Mathematics
1 answer:
Sauron [17]3 years ago
4 0

Answer:

a) 1

b)I would like to help u but i don't understand the question I think something is missing there plus sign or minus sign sry

Step-by-step explanation:

2.5x + 1.25 < 3.75

2.5x < 3.75 - 1.25

2.5x < 2.5

\frac{2.5x}{2.5}  =  \frac{2.5}{2.5}

x = 1

I hope u like it ‍❤️‍‍❤️‍

For any question comment me

Really sorry for the second question

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Misha Larkins [42]

Answer:

P'(7,0)Q'(2,1) R'(12,-6)

Step-by-step explanation:

P(3,5)------>P'(3+4,5-5)

P'(7,0)

Q(-2,6)----->Q'(-2+4,6-5)

Q'(2,1)

R(8,-1)------>R'(8+4,-1-5)

R'(12,-6)

8 0
4 years ago
Write the equation of a line through points (5, 5) and (1, 0) in point-slope form
klasskru [66]

Answer:

y=(5/4)x-5/4

Step-by-step explanation:

First we need to find the slope:

\frac{y_{2}-y_{1} }{x_{2}-x_{1} }

=\frac{5-0}{5-1}

=5/4

The SLops is 5/4

point-slope forum is

y=(5/4)x-5/4

(i think)

3 0
3 years ago
Twice a number is 12 more than five times the number
inna [77]
N x 2 = 12 + 5n
2n - 5n = 12
-3n = 12
3n = -12
n = -4
4 0
3 years ago
6 points
kodGreya [7K]

Answer:

y=-2\,(x+3)^2-3

Step-by-step explanation:

Notice that they are asking you to write the equation of the parabola in vertex form, that is using the coordinates of the vertex (x_v,y_v) in the expression:

y-y_v=a\,(x-x_v)^2\\y=a\,(x-x_v)^2+y_v

we can start by directly replacing the given vertex coordinates (-3, -3) in the expression, and then using the extra info on the point the parabola goes through in order to find the parameter a:

y=a\,(x-x_v)^2+y_v\\y=a\,(x+3)^2+(-3)\\y=a\,(x+3)^2-3\\-5=a\,(-2+3)^2-3\\-5=a\,(1)-3\\a=-5+3\\a=-2

So, now we can write the full expression for the parabola:

y=a\,(x+3)^2-3\\y=-2\,(x+3)^2-3

8 0
3 years ago
A genetics experiment involves a population of fruit flies consisting of 1 male named Bart and 3 females named Charlene, Diana,
kenny6666 [7]

Answer:

(b) \frac{1}{2}

Step-by-step explanation:

1 male named Bart (b)

3 females named Charlene(c), Diana(d), and Erin(e).

Since there is replacement, the possible samples are:

bb, bc, be, bd, cb, cc, cd, ce, db, dc, dd, de, eb, ec, ed, and ee.

Total Number of pairs = 16

Event of picking 2 males:bb

Event of 1 male:bc,cb,bd,db,be,eb

Event of picking 0 males:

cc, cd, ce, dc, dd, de, ec, ed, and ee.

\begin{equation*} \begin{matrix}Proportion of males & Probability \\0 & 9/16 \\1 & 6/16 \\2 & 1/16 \end{matrix} \end{equation*}

b. The mean of the sampling distribution

\mu = (\frac{9}{16} X0 ) +(\frac{6}{16} X 1)+(\frac{1}{16} X 2) = \frac{8}{16} = \frac{1}{2}

c.  No; the proportion of males is \frac{1}{4} while the mean is \frac{1}{2}.

B. No, the sample mean is not equal to the population proportion of males. These values are not always equal, because proportion is an unbiased estimator.

7 0
3 years ago
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