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2 years ago

What’s the correct answer ?

Mathematics

2 answers:

Vlad1618 [11]2 years ago

5 0

Answer: The Answer is D

<X is equal to <A

<Z is equal to <C

<Y is equal to <B

dangina [55]2 years ago

4 0

I think the answer is C

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Can Someone Explain? The Question Is In The Picture!

Amiraneli [1.4K]

$(256)^{\tfrac 14}\\\\=(4^4)^{\tfrac 14}\\\\=4^{\tfrac 44}\\\\=4^1 \\\\= 4\\\\\\27^{\tfrac 13}\\\\=(3^3)^{\tfrac 13}\\\\=3^{\tfrac 33} \\\\=3^1\\\\=3$

8 0

2 years ago

phyllis invested 66000 dollars, a portion earning simple interest rate of 5% per year and the rest earning a rate of 7% per year

Lelechka [254]

<u>Answer: </u>

Physliis invested 32000 dollar at 5% interest rate and 34000 dollar at 7% interest rate.

<u>Solution:</u>

Let Phyllis invest ‘x’ dollar at 5% per year and (66000-x) dollar at 7% per year.

We know,

$\text { Simple interest }=\frac{\text {Principal} \times r a t e \times T i m e}{100}$

In the question it is given that Simple interest earned from both the investments at the end of the year is $3980.

Using the given below equation, we will try to find out the investments at each rate.

$\begin{array}{l}{\frac{x \times 5 \times 1}{100}+\frac{(66000-x) \times 7 \times 1}{100}=3980} \\\\ {\frac{5 x}{100}+\frac{462000-7 x}{100}=3980} \\\\ {\frac{5 x+462000-7 x}{100}=3980} \\\\ {-2 \mathrm{x}+462000=3980 \times 100} \\\\ {-2 \mathrm{x}=398000-462000} \\\\ {-2 \mathrm{x}=-64000} \\\\ {\mathrm{x}=\frac{-64000}{-2}}\end{array}$

x = 32000

We can calculate amount for 7% interest rate by,

(66000-32000) =34000

Thus Phyllis invested 32000 dollar at 5% interest rate and 34000 dollar at 7% interest rate.

8 0

3 years ago

If $15,000 is invested at an interest rate of 2% per year, compounded semiannually, find the value of the investment after the g

Gennadij [26K]

Answer:

Step-by-step explanation:

If $10,000 is invested at an interest rate of 2% per year, compounded semiannually, find the value of the investment after the given number of years. (Round your answers to the nearest cent.)

a)6 years

b)12 years

c)18 years

***

compound interest formula: A=P(1+r/n)^nt, P=initial investment, r=interest rate, n=number of compounding periods per year, A=amt after t-years.

For given problem:

P=10000

r=.02

n=2

t=6, 12, 18

A(6)=10000(1+.02/2)^2*6

A(6)=10000(1.01)^12=11,268.25

A(12)=10000(1.01)^24=12,697.35

A(18)=10000(1.01)^36=14,307.69

3 0

3 years ago

Does it have extra information or missing information

mamaluj [8]

She wants to type her essay is the extra

4 0

3 years ago

Read 2 more answers

What is the product of 2x(x-4)

aliya0001 [1]

The answer to your question is $2x^2 - 8x$

8 0

3 years ago