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Svetradugi [14.3K]
3 years ago
6

If earth did not rotate what would happen to the hlobal wind

Chemistry
1 answer:
Readme [11.4K]3 years ago
8 0
It would probably stop moving. Earth has motion and we do do. without the world moving, there would be No wind at all.
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Calculate the pH of a 0.09 M solution of HBr​
jek_recluse [69]
12g6Don’t use that link!! They always comment under my stuff and other people have told me that’s just to get your information and location and stuff like that! Be safe and have a nice day!
3 0
3 years ago
ASAP Which of these mixtures would best be separated through distillation?
sveta [45]

Answer:

Water and acetone is best by separated through distillation

The correct answer would be option C Acetone and water.

Explanation:

When in a mixture of fluid solution, two liquids are mixed in a form of mixture then these liquid can be separated only one method which is based on the fact. That two different liquids will have two different boiling temperatures which method of separating the Fluids is distillation.  

The different liquids that are  present in mixture are boiled and the vapours are condensed and the condensed portion is  accumulated in another beaker.

4 0
3 years ago
_______________ is when a compound containing carbon and hydrogen (and sometimes oxygen) combines with oxygen gas to produce car
kotykmax [81]

Answer:

C. Combustion

Explanation:

Combustion- an organic compound containing carbon, hydrogen and sometimes oxygen reacts  with oxygen gas to form carbon dioxide and water.

4 0
3 years ago
The equilibrium constant for the following reaction: H2(g) + Br2(g) ↔ 2HBr (g) is 1.65 x 103 at a certain temperature. Find the
Aleks [24]

Answer:

6.97 atm was the equilibrium pressure of HBr .

Explanation:

The value of the equilibrium constant =K_p=1.65\times 10^3

H_2+Br_2\rightleftharpoons 2HBr

Initially:

0             0                 7.10 atm

At equilibrium

x              x                 (7.10-2x)

The expression of equilibrium constant can be written as:

K_p=\frac{p_{HBr}}{p_{H_2}\times p_{Br_2}}

1.65\times10^3=\frac{(7.10-2x)}{x^2}

Solving for x:

x = 0.065

Partial pressure of HBr at equilibrium :(7.10 - 2 × 0.065) atm = 6.97 atm

6.97 atm was the equilibrium pressure of HBr .

7 0
3 years ago
The equilibrium reaction below has the Kc = 0.254 at 25°C. If the temperature of the system at equilibrium is decreased to 0°C,
tia_tia [17]

Answer:

The equilibrium shifts towards reagents

Explanation:

Is known Kc=\frac{[products]}{[reagents]}  rised to the power of their number of moles in the balanced reaction. When you have a system at equilibrium with Kc < 1, it means [products] < [reagents] and the system needs energy to react, so if you decrease tempeture the equilibrium shifts towards reagents and less products will be created.

This efect can be discribed with Van´t Hoff equation: ln(\frac{K1}{K2}) =-\frac{dH}{R} (\frac{1}{T1} -\frac{1}{T2} ) where we can see that if we decrease temperature (this is T2<T1) in consecuense K2<K1 and reaction doesn´t happen.

7 0
3 years ago
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