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nydimaria [60]
1 year ago
13

You run an experiment in which two substances chemically react in a closed system. you run the same experiment in an open system

. how would the masses of the products in each experiment compare? explain.
Chemistry
1 answer:
m_a_m_a [10]1 year ago
6 0

If we run an experiment in which two substances chemically react in a closed system and then we run the same experiment in an open system, then the masses of the products in each experiment will be different because the open system allows the interchange of matter and energy with the media.

<h3>What is an open system?</h3>

An open system is an interrelated group pf parts that work together to interchange matter and energy with the surrounding environment, while a closed system does not generate an exchange of matter and energy.

Therefore, with this data, we can see that an open system interchange energy and matter with the environment, while closes systems do it.

Learn more about open systems here:

brainly.com/question/28891854

#SPJ1

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svp [43]

Answer:

C. Splitting the atom

Explanation:

splitting the atom involves fission

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3 years ago
Read 2 more answers
Enter the coefficients that balance the tarnishing
olga55 [171]

Answer:

2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)

Explanation:

Step 1: Data given

Ag(s) + H2S(g) → Ag,S(s) + H2(g)

Ag has and oxidation number of +1

S has an oxidation number of -2

H has an oxidation number of +1

Step 2: The balanced equation

Ag+ + 2H+ + S^2- →

The silver ion and the sulfur ion will bind, but we need 2 silver atoms to bind with 1 sulfur atom.

2 H- atoms will appear as H2.

The balanced equation is:

2Ag+ + 2H+ +S^2- → Ag2S + H2

2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)

7 0
3 years ago
What stops gravity from pulling water to the center of the earth
Alona [7]

Magnetism, or more specifically electromagnetic repulsion

4 0
3 years ago
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4Al(s)+3O2(g)__&gt; 2Al2O3(s)
nasty-shy [4]
What do you want us to work out?
8 0
3 years ago
Write the fraction of the mass of kcl produced from 1 g of k2c03​
Minchanka [31]

Mass of KCl= 1.08 g

<h3>Further explanation</h3>

Given

1 g of K₂CO₃

Required

Mass of KCl

Solution

Reaction

K₂CO₃ +2HCl ⇒ 2KCl +H₂O + CO₂

mol of K₂CO₃(MW=138 g/mol) :

= 1 g : 138 g/mol

= 0.00725

From the equation, mol ratio K₂CO₃ : KCl = 1 : 2, so mol KCl :

= 2/1 x mol K₂CO₃

= 2/1 x 0.00725

= 0.0145

Mass of KCl(MW=74.5 g/mol) :

= mol x MW

= 0.0145 x 74.5

= 1.08 g

6 0
3 years ago
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