Answer:
To remedy the stability problem, Bohr modified the Rutherford model by requiring that the electrons move in orbits of fixed size and energy.
Answer:
45.98 I believe if its wrong im sorry
No , it’s a carboxylic Easter
I assume that the answers would be
2) is "A"
3) is "D"
Answer:
The freezing point will be -2.046°C.
Explanation:
The freezing point depression equation is
Where;
= The temperature depression of the freezing point
= The constant of freezing point depression which is solvent dependent = 1.86°C/m
i = The number of particles the substance decomposes into in solution = 1 for sugar (a covalent compound)
m = The molality of the solution = 1.1
Therefore, we have;
Therefore the freezing point will be 0 - 2.046°C = -2.046°C.