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-Dominant- [34]
3 years ago
7

The shininess of an element is also referred to as "metallic luster." which of the following elements is most likely to have a m

etallic luster?
a. arsenic
b. rhodium
c. chlorine
d. hydrogen
Chemistry
1 answer:
lisov135 [29]3 years ago
4 0
<span>The shininess of an element is also referred to as "metallic luster." The element that is most likely to have a metallic luster is B. rhodium.
Arsenic has a dull luster, chlorine and hydrogen are gases so they don't have luster.
</span>
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Which of the following processes would you predict to have an increase in entropy?
Anna [14]
C. Melting ice. 
It is C because melting ice is a change of state from solid to liquid which requires an addition of energy(or entropy) into the system.
Condensation of water occurs from a gas to a liquid state, which takes energy out of the system(water) and gives it to the surroundings(air around it). Freezing water is the same as condensation except for the state change. Deposition is simply gas to a solid instantaneously so you can again see it as with the other two examples. 

6 0
3 years ago
Why bond angle of H2O is maximum then OF2??
Nataly_w [17]
It's lone a little distinction (103 degrees versus 104 degrees in water), and I trust the standard rationalization is that since F is more electronegative than H, the electrons in the O-F bond invest more energy far from the O (and near the F) than the electrons in the O-H bond. That moves the powerful focal point of the unpleasant constrain between the bonding sets far from the O, and thus far from each other. So the shock between the bonding sets is marginally less, while the repugnance between the solitary matches on the O is the same - the outcome is the edge between the bonds is somewhat less.
8 0
3 years ago
What contribution did these scientists make to atomic models of the atom?
SashulF [63]

Answer:

Explanation:

Dalton's atomic theory proposed that all matter was composed of atoms, indivisible and indestructible building blocks. While all atoms of an element were identical, different elements had atoms of differing size and mass.

In 1897, J.J. Thomson discovered the electron by experimenting with a Crookes, or cathode ray, tube. He demonstrated that cathode rays were negatively charged. In addition, he also studied positively charged particles in neon gas.

Rutherford overturned Thomson's model in 1911 with his well-known gold foil experiment in which he demonstrated that the atom has a tiny and heavy nucleus. Rutherford designed an experiment to use the alpha particles emitted by a radioactive element as probes to the unseen world of atomic structure.

The Bohr model shows the atom as a small, positively charged nucleus surrounded by orbiting electrons. Bohr was the first to discover that electrons travel in separate orbits around the nucleus and that the number of electrons in the outer orbit determines the properties of an element.

7 0
3 years ago
Mitosis and Meiosis Lab Report
poizon [28]

Answer:

Mitosis and Meiosis Lab Report

Instructions: In the Mitosis and Meiosis lab, you investigated sexual and asexual reproduction as well as the processes of cellular division by mitosis and meiosis. Record your observations in the lab report below. You will submit your completed report.

________________________________________

Name and Title:  

Mitosis and Meiosis Lab Report.  

Objective(s):  

To learn and explore what mitosis and meiosis is and what they do.  

Hypothesis:

Record your predictions during the zoo tour section of the lab in the data chart.

Procedure:

First, go into the mitosis and meiosis cycles. Then look at what happens when a sex cell from a female tiger is combined with a sex cell from a male tiger. Then investigate what happens when two starfish reproduce asexually. Then write down the predictions about how each organism will replicate. Then, keep track on whether or not the forecast was right.

Data:  

Record your data from the zoo tour in the data chart below. Be sure to fill in the chart completely.

Zoo Organism Reproduction Prediction

(sexual, asexual, or both) Reproduction Result

(sexual, asexual, or both)

Elephant Sexual Sexual

Whiptail lizard Asexual Asexual

Parrot Sexual Sexual

Redwood tree  Both Both

Amoeba Asexual Asexual

Jellyfish Asexual Both

Conclusion:  

Your conclusion will include a summary of your lab results and an interpretation of the results. Please write in complete sentences.

1. List one-way mitosis and meiosis are the same and one way they are different.

Meiosis has 2 cell divisions, but mitosis has just one cell division. Since the parent cell develops diploid cells, meiosis I is the same as mitosis. The distinction between meiosis and mitosis is that after the whole process, meiosis produces genetically distinct haploid daughter cells, while mitosis produces genetically identical diploid daughter cells.

2. What is one advantage and one disadvantage of sexual reproduction?

The greatest benefit of sexual reproduction is that it aids in the development of offspring that are well suited to environmental environments due to genetic differentiation. As a result, the nation has a diverse range of descendants. The downside is that it needs two parents and takes longer than asexual reproduction.

3. What is one advantage and one disadvantage of asexual reproduction?

Asexual reproduction has the advantage of requiring only one parent, taking a short amount of time, and producing genetically identical offspring. The only drawback is that when there is a catastrophe, the mortality rate is poor due to the generation of genetically identical offspring.

4. Some living organisms are capable of both asexual and sexual reproduction. Explain how this can be an advantage.

To produce offspring, the organism may use either sexual or asexual reproduction. If it is difficult to find a mate, the living being will use asexual reproduction to produce offspring quickly. Sexual reproduction is possible because the individual requires genetically distinct offspring for survival.

Explanation:

Try to paraphrase evrything. I already paraphrased the procedure but i reccomend using the website "quillbot" to paraphrase evrything else so you dont get in trouble! If you have any qustions im here to answer ;)

6 0
3 years ago
Read 2 more answers
Suppose an ice cube weighing 36.0 g at a temperature of 10°C is placed in 360 g water at a temperature of 20°C. Calculate the te
Scilla [17]

Answer:

10.44 °C

Explanation:

When the thermal equilibrium is reached, both of the substances have the same final temperature (T). The liquid water will lose heat, and the ice cube will absorb this heat. The temperature of the ice will increase until it reaches 0°C, at this temperature, it will change of phase for liquid, absorbing heat, but without a change in the temperature. Then the temperature will increase until the equilibrium.

By the energy conservation, the total amount of heat must be equal to 0:

Qice + Qmelting + Qliquid1 + Qliquid2 = 0

Liquid 1 is the ice after melting, and liquid 2 the liquid that was already at the flask. When there's a change of temperature:

Q = n*c*ΔT, where n is the number of moles, c is the heat capacity and ΔT is the temperature change (final - initial). The temperature variation in °C is equal in K, so the temperature may be used in °C.

The melting heat is:

Q = n*Hfus, Hfus = 6007 J/mol

The molar mass of the water is 18 g/mol, so the number of moles of the water and the ice are:

nwater = nliquid1 = 360/18 = 20 moles

nice = 36/18 = 2 moles

Qice + Qmelting + Qliquid1 + Qliquid2 = 0

2*38*(0 - (-10)) + 2*6007 + 2*75*(T - 0) + 20*75*(T - 20) = 0

760 + 12014 + 150T + 1500T - 30000 = 0

1650T = 17226

T = 10.44 °C

4 0
3 years ago
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