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Phantasy [73]
3 years ago
7

Solve the following equation for y.

Mathematics
2 answers:
Paladinen [302]3 years ago
5 0

Answer:

<h2>Y=17</h2>

Step-by-step explanation:

To solve for a variable, first you have to isolate it on one side of the equation.

First, you do is subtract 2 from both sides.

2y-2+2=36-2

Then, you simplify.

36-2=34

2y=34

Next, you divide 2 from both sides.

2y/2=34/2

Finally, simplify.

34/2=17

<h2>Therefore, the correct answer is y=17. </h2><h2>Hope this helps! </h2><h2>Thank you for posting your question!</h2>
labwork [276]3 years ago
3 0

Answer:

17

Step-by-step explanation:

2y+2=36

Let's solve this equation for 2y first.  This means get 2y by itself.

So to get 2y by itself I need to undo that addition of 2 next to it.

The inverse operation of addition is subtraction.

I'm going to subtract 2 on both sides:

2y      =36-2

2y      =34

Now we want to get y by itself so we divide both sides by 2 since division and multiplication are inverse operations:

 y=        34/2

 y=        17

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What are the coordinates of the point (-1,9) after a clockwise rotation of 90 degree about the origin
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3 years ago
I need help finding which angles are supplementary to eachother
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BlackZzzverrR [31]
-3^2= -(3)^2

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5 0
3 years ago
The average age of staff in the maths department is 40.
pashok25 [27]

Answer:

Cerian is 28 years old

Step-by-step explanation:

The given parameters are;

The average age of the staffs in the mathematics department = 40

The number of staffs in the department = 7

The average age of Jill, Nicky and Wendy = 41

The average age of Andy, Alan and Cathy = 43

From the given parameters, we have;

The average age of the staffs in the mathematics department = (The sum total of the ages of the members of the math department)/(The number of staffs in the department)

Therefore;

40 = (The sum total of the ages of the members of the math department)/ (7)

From which we have;

The sum total of the ages of the members of the math department = 40 × 7 = 280

Which gives;

Jill's age + Nicky's age + Wendy's age + Cathy's age + Cerian's age + Alan's age + Andy's age = 280 years

The average age of Jill, Nicky and Wendy = 41

Given that Jill, Nicky, and Wendy make up 3 of the 7 members of staffs, we have;

The average age of Jill, Nicky and Wendy = (The sum total of the ages of Jill, Nicky, and Wendy)/(The number of staff Jill, Nicky, and Wendt make)

Therefore;

The sum total of the ages of Jill, Nicky, and Wendy = 41 × 3 = 123

Which gives;

Jill's age + Nicky's age + Wendy's age = 123 years

Similarly, the sum total of the ages of Andy, Alan, and Cathy = 43 × 3 = 129

Which gives;

Andy's age + Alan's age + Cathy's age = 129 years

Therefore;

Cerian's age = (Jill's age + Nicky's age + Wendy's age + Cathy's age + Cerian's age + Alan's age + Andy's age) - (Jill's age + Nicky's age + Wendy's age) + (Andy's age + Alan's age + Cathy's age)

∴ Cerian's age = 280 years - 123 years - 129 years = 28 years

6 0
3 years ago
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