Answer: Perimeter = 66 cm and area =
Step-by-step explanation:
The perimeter of rectangle is given by :-
, where l is length and w is width of the rectangle.
Given : A rectangle has a length of 5.50 m and a width of 12.0 m .
Then, the perimeter of rectangle :

Also, area of rectangle is given by :-

Area of rectangle = 
The answer $32.62........
Answer:
The first step should be adding 14 to both sides of the equation.
Step-by-step explanation:
14 must be added on both sides of the equation to get 13y by itself. The ultimate goal is to get y by itself if we are solving for y.
Once 14 is added on both sides, you'll get:
13y = 56.
Then 13 would be divided from both sides.
y = 4.3
Step-by-step explanation:

Answer:
y = -2.8x +69.4
Step-by-step explanation:
Let y represent units of inventory, and x represent days since the last replenishment. We are given points (x, y) = (3, 61) and (13, 33). The line through these points can be described using the 2-point form of the equation of a line:
... y -y1 = (y2-y1)/(x2 -x1)(x -x1)
Filling in the given point values, we have ...
... y -61 = (33 -61)/(13 -3)(x -3)
Simplifying and adding 61, we get ...
... y = -2.8x +69.4