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2 years ago

Which of the following equations represents a line that is parallel to the line that passes through the points below?

Mathematics

1 answer:

Pepsi [2]2 years ago

3 0

Answer:

See below

Step-by-step explanation:

Two lines are parallel if they have the same slope but different y-intercepts. So the slope that can be formed given the points (-3,6) and (9,2) is (9-(-3))/(2-6)=12/-4=-3

With y=-3x+b, we need b, which can be found by plugging in either point:

2=-3(9)+b

2=-27+b

29=b

So the y-intercept therefore cannot be 29 but it can be any real number.

So the equation y=-3x+2 works, y=-3x+3, y=-3x+4, and so on....

You might be interested in

What is 520 divided by 8

erastova [34]

First see how many times can 8 go into 52. So 8 goes 6 times, and it equals to; 48
Now subtract 48 from 52; 52-48= 4

Finally bring down the 0 next to the 4; 40

Now to get you final answer find out how many times can 8 go into 40; 5
Since it goes exactly 5 times then your final answer would be; 65
Hope this helps! :)

7 0

2 years ago

Which trigonometric functions are negative in the fourth (IV) quadrant?

anzhelika [568]

<h3>Answers are: sine, tangent, cosecant, cotangent</h3>

Explanation:

On the unit circle we have some point (x,y) such that x = cos(theta) and y = sin(theta). The sine corresponds to the y coordinate of the point on the circle. Quadrant IV is below the x axis which explains why sine is negative here, since y < 0 here.

Since sine is negative, so is cosecant as this is the reciprocal of sine

csc = 1/sin

In quadrant IV, cosine is positive as x > 0 here. So the ratio tan = sin/cos is going to be negative. We have a negative over a positive when we divide.

Because tangent is negative, so is cotangent.

The only positive functions in Q4 are cosine and secant, which is because sec = 1/cos.

7 0

2 years ago

Fifteen seventh graders were randomly selected to see how many pushups in a row they could do. Their data are shown. a. b. 45, 4

GuDViN [60]

Answer: Median = 42

Mean = 43.8

Step-by-step explanation:

When we have a data set of n points {x₁, x₂, ..., xₙ}

The mean is written as:

(x₁ + ... + xₙ)/N

And the median will be the value in the middle of the data set.

So first, let's write our data set in order, from least to greatest.

{36, 36, 38, 40, 40, 40, 42, 42, 43, 45, 45, 48, 48, 70}

So we have 14 values.

The middle value will be at:

(n + 1)/2

(14 + 1)/2 = 7.5

Now, counting from the left, we have that the 7.5th value is 42. (the 7th value is 42, and the 8th value is 42)

So the median is 42.

Now the mean:

M = (36 + 36 +38 +40+40+40+ 42 +42 + 43 + 45 + 45 + 48 + 48 + 70)/14

M = 43.8

8 0

2 years ago

น. <br><img src="https://tex.z-dn.net/?f=x%20%3D%201%20-%20%20%5Csqrt%7B2%7D%20find%20%20%5C%3A%28x%20-%20%20%5Cfrac%7B1%7D%7Bx%

Nastasia [14]

Answer:

Step-by-step explanation:

$\frac{1}{x}=\frac{1}{1-\sqrt{2}}\\\\=\frac{1*(1+\sqrt{2})}{(1-\sqrt{2})(1+\sqrt{2})}\\\\=\frac{1+\sqrt{2}}{1^{2}-(\sqrt{2})}\\\\=\frac{1+\sqrt{2}}{1-2}\\\\=\frac{1+\sqrt{2}}{-1}\\\\= -[1+\sqrt{2}]\\\\x-\frac{1}{x}=1-\sqrt{2}-(-[1+\sqrt{2}])\\\\=1-\sqrt{2}+1+\sqrt{2}\\\\=2$

8 0

2 years ago

At work, Jack must stuff 1000 envelopes with advertisements. He can stuff 12 envelopes in one minute, and he has 112 envelopes a

Vsevolod [243]

Answer:

It will take Jack 74 minutes(1 hour and 14 minutes) to complete the task

Step-by-step explanation:

From the question, we know that he has 1000 envelopes to stuff.

Now, he has already stuffed 112 out of the 1000. Number of envelopes left to be stuffed will be 1000 -112 = 888 envelops

We were told that it takes him 1 minute to stuff 12 envelopes.

Let the time it will take him to stuff 888 envelopes be x minutes;

Let’s have a relationship here;

12 envelopes = 1 minute

888 envelopes = x minutes

12 * x = 888 * 1

12x = 888

x = 888/12

x = 74 minutes

4 0

2 years ago