Simplify. 1/4√8n √2n^3

My question is y = 4x + 1 and my options are<br>a. 4, 3 <br>b. 4,1<br>c. 1,4<br>d. 3,1

Akimi4 [234]

Answer:

B. 4,1

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

5x + 4m = 43my + 6 solve for m

pav-90 [236]

9514 1404 393

Answer:

m = (5x -6)/(43y -4)

Step-by-step explanation:

Subtract 4m+6 to separate m-terms from other terms.

5x +4m -(4m +6) = 43my +6 -(4m +6)

5x -6 = 43my -4m

5x -6 = m(43y -4) . . . . factor out m

(5x -6)/(43y -4) = m . . . . divide by the coefficient of m

7 0

2 years ago

Plz help meeeeeeeeeee

PSYCHO15rus [73]

Answer:

Please check the explanation.

Step-by-step explanation:

We know the equation

y = kx

k = y/x

where k is the proportionality constant

so,

First ratio can be calculated as

Miles = 45

Hours = 3/4

The ratio = 45 / (3/4)

= (45 × 4) / 3

= 180/3

= 60

Thus, the proportionality constant = 60

Thus, the remaining ratios can be calculated as:

The Pair (135, Hours)

135/Hours = 60

Hours = 135 / 60

= 27/12

= 9/4

= 2.25

Thus, the pair is (135, 2.25)

The Pair (Miles, 3)

Miles/3 = 60

Miles = 60×3

= 180

The Pair (90, Hours)

90/Hours = 60

Hours = 90 / 60

= 3/2

= 1.5

Thus, the complete table:

Miles 45 135 180 90

Hours 3/4 9/4 3 3/2

Verification:

Miles / Hour = 45/(3/4) = 60

Miles / Hour = 135 / 2.25 = 60

Miles / Hour = 180 / 3 = 60

Miles / Hour = 90 / 1.5 = 60

8 0

2 years ago

NarStor, a computer disk drive manufacturer, claims that the median time until failure for their hard drives is more than 14,400

Ne4ueva [31]

Answer:

The test statistics is $t = -1.727$

Step-by-step explanation:

From the question we are told that

The data given is

330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814

The population mean is $\mu = 14400$

The sample size is n = 16

The null hypothesis is $\mu \le 14400$

The alternative hypothesis is $H_a : \mu > 14400$

The sample mean is mathematically evaluated as

$\= x = \frac{\sum x_i}{n}$

So

$\= x = \frac{330+ 620+ 1870 +2410+ 4620+ 6396+ 7822+ 8102+8309+ 12882+ 14419+ 16092+ 18384 +20916+ 23812+ 25814 }{16}$

=> $\= x = 10799.9$

The standard deviation is mathematically represented as

$\sigma =\sqrt{\frac{ \sum (x_i - \=x)^2}{n}}$

So

$\sigma =\sqrt{\frac{(330- 10799.9)^2 + (620- 10799.9)^2+ (1870- 10799.9)^2 +(2410- 10799.9)^2 + (4620- 10799.9)^2 +(6396- 10799.9)^2 +(7822- 10799.9)^2 }{16}} \ ..$

$..\sqrt{ \frac{(8102 - 10799.9)^2 +(8309 - 10799.9)^2 + (12882 - 10799.9)^2 + (14419 - 10799.9)^2 + (16092 - 10799.9)^2 + (18384 - 10799.9)^2 +(20916 - 10799.9)^2 }{16}} \ ...$