This should be quite easy to explain. So the first thing you want to do is multiply them. This isn't to hard if you know your times tables. Don't worry about the decimal till the end.
15.37
× 5
---------
76.85
15.37 times 5 is 76.85
Now on to the decimal. All you need to do is move it two times to the left. You see how it's in between the 5 and 3? The same goes for your answer. So it is 76.85
I hope this helped!! ^^ I can make this a little more easier to explain if you want me to just in case, ok?
Answer:
-3.9/1
Step-by-step explanation:
Answer:
Independent Sampling
Step-by-step explanation:
There are two scenarios for independent sampling .
Testing the mean we get the differences between samples from each population. When both samples are randomly inferences about the populations. can get.
Independent sampling are sample that are selected randomly. Observation does not depend upon value.Many analysis assume that sample are independent.
In this statement 90 dash are divides into two groups Group 1 and Group 2 . Both are standardized that mean both are randomly selected. Means are observed. Observation doesn't depend upon value. So this style of sampling is independent Sample.
When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2
<h3>Data obtained from the question</h3>
- [(x^2)^3 × 5x] / [6x^2 × 15x^3]
- Simplification =?
<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>
[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Recall
(M^a)^b = M^ab
Thus,
(x^2)^3 = x^6
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]
Recall
M^a × M^b = M^(a+b)
Thus,
x^6 × 5x = 5x^(6 + 1) = 5x^7
6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5
- [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5
Recall
M^a ÷ M^b = M^(a - b)
Thus,
5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2
Therefore,
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2
Learn more about algebra:
brainly.com/question/2768008
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Answer:
the drop in the level of water in the container is 2.03 cm
Step-by-step explanation:
The volume of a cylinder can be written as;
the change in height when the volume changes can be derived by differentiating the equation.
substituting the given values;
the drop in the level of water in the container is 2.03 cm
