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3 years ago

-3a + 6b= a + 4b Write a formula for f (a) in terms of a.

Mathematics

2 answers:

belka [17]3 years ago

7 0

Answer:The formula for a can be calculated by the following steps;

Step-by-step explanation:

-3a-a=4b-6b

-4a=-2b

cancelling the negative sign;

4a=2b

a=2b/4

a=b/2

Mariulka [41]3 years ago

3 0

Answer:

f(a)=2a

Step-by-step explanation:

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List the angles in triangle QRS from smallest to largest.

schepotkina [342]

Answer:

angle R

Step-by-step explanation:

To solve this we will use cosine rule

Cosine rule

cos(A) = $\frac{b^{2}+c^{2}-a^{2}}{2bc}$

suppose,

q = 6.25

s = 11.04

r = 13.19

angleQ = $cos^{-1}(\frac{13.19^{2}+11.04^{2}-6.52^{2}}{2(13.19)(11.04)})$

= 30.58

angleR = $cos^{-1}(\frac{6.52^{2}+11.04^{2}-13.19^{2}}{2(6.52)(11.04)})$

= 93.82

angleS = $cos^{-1}(\frac{6.52^{2}+13.19^{2}-11.04^{2}}{2(6.52)(13.19)})$

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3 years ago

What is the median of the data set? 15, 19, 20, 22, 26, 30, 31

Paladinen [302]

Answer:

C. 22

Step-by-step explanation:

The median is the middle number of the set if the numbers are in order from least to greatest.

This set of numbers is in order, so the median is the middle number = 22

7 0

2 years ago

Need help with math question

mote1985 [20]

Answer:

(-7,4)

Step-by-step explanation:

goal: (y-k)^2=4p(x-h)

y^2-8y=4x+12 Rearranged and added 4x and 12 on both sides

y^2-8y+(-8/2)^2=4x+12+(-8/2)^2 complete square time (add same thing on both sides)

y^2-8y+(-4)^2=4x+12+(-4)^2 (simplify inside the squares)

(y-4)^2=4x+12+16 (now write the left hand side as a square)

(y-4)^2=4x+28

(y-4)^2=4(x+7) factored...

vertex is (-7,4)

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3 years ago

Read 2 more answers

Help me please? I’ll make u the brainliest

drek231 [11]

Answer:

answer is (3,7)

Step-by-step explanation:

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3 years ago

Find the average value of the function on the given interval.<br> f(x)=ex/7; [0,7]

Anastaziya [24]

Answer:

$f_{avg}=e-1$

Step-by-step explanation:

We are given that a function

$f(x)=e^{\frac{x}{7}}$

We have to find the average value of function on the given interval [0,7]

Average value of function on interval [a,b] is given by

$\frac{1}{b-a}\int_{a}^{b}f(x)dx$

Using the formula

$f_{avg}=\frac{1}{7-0}\int_{0}^{7}e^{\frac{x}{7}} dx$

$f_{avg}=\frac{1}{7}[e^{\frac{x}{7}}\times 7)]^{7}_{0}$

By using the formula

$\int e^{ax}=\frac{e^{ax}}{a}$

$f_{avg}=(e-e^0)=e-1$

Because $e^0=1$

$f_{avg}=e-1$

Hence, the average value of function on interval [0,7]

$f_{avg}=e-1$

8 0

3 years ago