Answer:
A) 8,368 J
B) ) 0.893 J/gºC
Explanation:
A)
- The heat gained by the water can be obtained solving the following equation:
- where cw = specific heat of water = 4.184 J/gºC
- m= mass of water = 1,000 g
- ΔT = 2ºC
- Replacing these values in (1) we get:
B)
- Assuming that the heat energy gained by the water is equal to the one lost by the aluminum, we can use the same equation, taking into account that the energy is lost by the aluminum, so the sign is negative: -8,368 J.
- Replacing by the mass of aluminum (125 g), and the change in temperature (-74.95ºC), in (1), we can solve for the specific heat of aluminum, as follows:
⇒
- which is pretty close to the Aluminum's accepted specific heat value of 0.900 J/gºC.
