3 years ago

How does an an electron microscope work?

Physics

2 answers:

Eddi Din [679]3 years ago

8 0

With electricity it work..

EastWind [94]3 years ago

5 0

<em>it works on the following principals:

</em>

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A curve that has a radius of 100 m is banked at an angle of θ = 10.4 ∘ . If a 1200 kg car navigates the curve at 65 km / h witho

Vika [28.1K]

Explanation:

Below is an attachment containing the solution.

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3 years ago

An elf pushes a sleigh with force of 9N over a distance of 11m. How much work did the elf. Do on the sleigh

Whitepunk [10]

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 9 × 11

We have the final answer as

Hope this helps you

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3 years ago

If the absolute pressure of a gas is 550.280 kPa, its gage pressure is

aivan3 [116]

By definition we have to:

$Pabs = Patm + Pg$

Where,

Pabs: absolute pressure

Patm: atmospheric pressure

Pg: gage pressure

The atmospheric pressure is constant and its value is:

$Patm = 101.325 kPa$

Then, by clearing gage pressure we have:

$Pg = Pabs - Patm$

Substituting values we have:

$Pg = 550.280 - 101.325\\Pg = 448.955 KPa$

Answer:

If the absolute pressure of a gas is 550.280 kPa, its gage pressure is:

D. 448.955 kPa

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3 years ago

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Calculate 9 ∙ 10-5 divided by 3 ∙ 10-9. (Box after the "10" in answer is for the exponent.).

Papessa [141]

Answer:

3 × 10⁴

Explanation:

We are given two numbers, $n_1=9\times 10^{-5}$ and $n_2=3\times 10^{-9}$

We have to divide n₁ by n₂. We know that,

$\dfrac{10^n}{10^m}=10^{n-m}$

Here, n = -5 and m = -9

So on dividing we get :

$\dfrac{9\times 10^{-5}}{3\times 10^{-9}}=3\times 10^{-5+9}=3\times 10^4$

Hence, on dividing n₁ by n₂ obtained number is 3 × 10⁴.

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3 years ago

How does the orbital speed of an asteroid in a circular solar orbit with a radius of 4.0 AU compare to a circular solar orbit wi

Murrr4er [49]

Answer:

The circular solar orbital speed at 4.0AU is 1/4( one fourth) that at 1.0AU

Explanation:

am = mvr= angular momentum

am4= 4mvt

am1= mvp1

Vt=1/4vp

Vp=4vt

am1= 4mvt

am1=am4

The circular solar orbital speed at 4.0AU is 1/4 (one fourth) that at 1.0AU

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4 years ago