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evablogger [386]

3 years ago

9

How does an an electron microscope work?

2 answers:

Eddi Din [679]3 years ago

8 0

With electricity it work..

EastWind [94]3 years ago

5 0

<em>it works on the following principals:

</em>

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elixir [45]

I d k you figure it out

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3 years ago

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A negatively charged iron ball on the end of a plastic rod exerts a strong attractive force on a penny even though the penny is

sasho [114]

The negatively charged rod cause charge migration within the penny. So, the protons and electrons in the penny move to seperate sides of the penny with the protons on the side closest to the iron ball. Then the penny could have been touched by a person or another object to ground the penny, removing the excess electrons in the penny. This is called charging by induction. So after grounding, the penny becomes positively charged. Opposite charges attract

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4 years ago

How can you recognize the potential greatness in others?

Nikolay [14]

Answer:

heres some ways i personally think might help!

Explanation:

Have a Compelling Vision. Your vision must be larger than yourself and larger than the moment, says world-famous business guru Tony Robbins. ...

Build Collaboration.

Be Focused.

Innovate.

Use Emotional Intelligence.

Pass Your Leadership On.

Leadership. Greatness in leaders is expressed though a positive attitude. ...

Service. To be of real service in this world, we must add something to other people's lives that cannot be bought. ...

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Efficiency.

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Recognize Effort and Hard Work, not Intelligence. ...

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5 0

3 years ago

You are on earth, and have an object with a mass of 7 kg. with how much force does the earth's gravity pull the object downward?

svp [43]

This is equivalent to asking the mass’s weight. Force=mass * acceleration. So 7*9.8= 68.6 N

6 0

4 years ago

Two long straight parallel wires separated by a distance of 20 cm carry currents of 30 A and 40 A in opposite directions. What i

irakobra [83]

Answer:

$B_{net} = 3.3 \times 10^{-5} T$

Explanation:

Magnetic field due to straight long wire is always perpendicular to the line joining the wire and the point

it is given by the equation

$B = \frac{\mu_0 i}{2\pi r}$

now the magnetic field due to 30 A current is given as

$B_1 = \frac{(2\times 10^{-7})(30)}{0.15}$

$B_1 = 4\times 10^{-5} T$

Now magnetic field due to other wire having current 40 A is given as

$B_2 = \frac{(2 \times 10^{-7})(40)}{0.25}$

$B_2 = 3.2 \times 10^{-5} T$

now net field along Y direction is given as

$B_y = B_2cos37$

$B_y = 2.56 \times 10^{-5} T$

now for X direction magnetic field we know

$B_x = B_1 - B_2sin37$

$B_x = (4\times 10^{-5}) - (3.2 \times 10^{-5}sin37)$

$B_x = 2.07 \times 10^{-5} T$

Now net magnetic field is given as

$B_{net} = \sqrt{B_x^2 + B_y^2}$

$B_{net} = \sqrt{2.56^2 + 2.07^2} \times 10^{-5} T$

$B_{net} = 3.3 \times 10^{-5} T$

7 0

4 years ago