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navik [9.2K]
3 years ago
10

25.0 mL of 0.212 M NaOH is neutralized by 13.6 mL of an HCl solution. The molarity of the HCl solution is

Chemistry
1 answer:
Semenov [28]3 years ago
4 0

Answer:

M_{HCl}=0.390M

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

HCl+NaOH\rightarrow NaCl+H_2O

In such a way, for the neutralization, the moles of sodium hydroxide must equal those of the hydrochloric acid considering their 1:1 molar ratio in the chemical reaction:

n_{HCl}=n_{NaOH}

Hence, in terms of molarities and volumes:

M_{NaOH}V_{NaOH}=M_{HCl}V_{HCl}

Thus, solving for the molarity of the hydrochloric acid solution we obtain:

M_{HCl}=\frac{M_{NaOH}V_{NaOH}}{V_{HCl}}=\frac{0.212M*25.0mL}{13.6mL}\\  \\M_{HCl}=0.390M

Best regards.

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