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Veronika [31]
3 years ago
8

Could someone please help me with my chemistry hw please please please please please please please

Chemistry
1 answer:
IceJOKER [234]3 years ago
3 0
Jhgpqurhubfjnqjejfnbouqejdnfcnadvq f/g
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If all the deer disappeared from this community, which change would be most
butalik [34]

Answer:c

Explanation:

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3 years ago
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Compare the modern (electron cloud) model of the atom with Bohr’s atomic model. Which of these statements describe the two model
AfilCa [17]

Answer:

B. Bohr’s model electrons cannot exist between orbits, but in the electron cloud model, the location of the electrons cannot be predicted.

AND

C. The modern model explains all available data about atoms; Bohr’s model does not.

Explanation:

The answers are right on Edge. :)

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An 11.75 g sample of a common hydrate of cobalt(ii) chloride is heated. after heating, 9.25 g of anhydrous cobalt chloride remai
Irina-Kira [14]
Hydrated salts are when salt crystals have water molecules bound. Anhydrous salts are when the water has been removed.
mass of water removed = hydrated salt - anhydrate salt 
                                       = 11.75 g - 9.25 g = 2.50 g
number of water moles  = 2.50 g / 18 g/mol = 0.139 mol 
number of cobalt (II) chloride moles = 9.25 g / 130 g/mol = 0.0712 mol 
ratio of water moles to CoCl₂ moles - 0.139 mol / 0.0712 mol = 1.95 
rounded off 2 moles of water for every 1 mol of CoCl₂
formula - CoCl₂.2H₂O
name - Cobalt(II) chloride dihydrate
3 0
3 years ago
How much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh
Sever21 [200]

Answer:

13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

Volume of the acid (Va) =?

Volume of the base (Vb) = 39mL

Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

6 x Va / 2 x 39 = 1/1

Cross multiply to express in linear form

6 x Va = 2 x 39

Divide both side by 6

Va = (2 x 39)/6

Va = 13mL

Therefore, the volume of the acid (HNO3) needed for the reaction is 13mL

5 0
3 years ago
How many moles in 5 grams of gold
Ainat [17]
There is 0.02538502095915 Moles in 5 grams of gold.
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