Answer:
hydrofluoric acid HF H+ + F- 7.2 × 10-4
Answer:
254.5 K
Explanation:
Data Given
initial volume V1 of neon gas = 12.5 L
final Volume V2 of neon gas = 10.5 L
initial Temperature T1 of neon gas = 30 °C
convert Temperature to Kelvin
T1 = °C +273
T1 = 30°C + 273 = 303 K
final Temperature T2 of neon gas = ?
Solution:
This problem will be solved by using Charles' law equation at constant pressure.
The formula used
V1 / T1 = V2 / T2
As we have to find out Temperature, so rearrange the above equation
T2 = V2 x T1 / V1
Put value from the data given
T2 = 10.5 L x 303 K / 12.5 L
T2 = 254.5K
So the final Temperature of neon gas = 254.5 K
First, we have to correct the equation in the question to b(g)⇆ 1/2 A(g)
at the first equation A(g)⇆ 2 B(g) so,
Kc = [B]^2 [ A] = 0.03
by reverse the equation 2B⇆ A
∴ Kc(original) = [A] / [B]^2
= 1/0.03 = 33 M^-1
and the new equation B⇆ (1/2) A
So, the new Kc = √Kc(original = √33
∴ KC = 5.7
An adiabatic process is when the system is insulated that no heat is released to the surroundings. For this type of process, we have a derived formula written below:
(T₂/T₁)^C = (V₁/V₂)
where C = Cv/nR
From the complete problem shown in the attached picture, Cv = (3/2)R. Thus,
C= (3/2)/1 mol = 3/2
(T₂/305 K)^(3/2) = (8.5 L/82 L)
Solving for T₂,
<em>T₂ = 67.3 K</em>