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alexira [117]
2 years ago
13

Enter an equation to show how h2po3− can act as a base with hs− acting as an acid. Express your answer as a chemical equation. I

dentify all of the phases in your answer.
Chemistry
1 answer:
vladimir2022 [97]2 years ago
4 0

The acid - base equation between H2PO3^- and HS^- is H2PO3^- +  HS^- ⇄S^- + H3PO3.

<h3>What is an acid?</h3>

An acid is a substance that can donate hydrogen ions while a base is a substance that can accept hydrogen ion. This is the acid base definition according to Brownstead - Lowry.

To show the acid - base relationship between H2PO3^- and HS^-, we have the equation;

H2PO3^- +  HS^- ⇄S^- + H3PO3

Learn more about acids and bases: brainly.com/question/10282816

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Answer:

silver

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3 years ago
In compliance with conservation of energy, Einstein explained that in the photoelectric effect, the energy of a photon (hv) abso
3241004551 [841]

Answer:

 a) 1.866 × 10 ⁻¹⁹ J      b)   3.685 × 10⁻¹⁹ J

Explanation:

the constants involved are

h ( Planck constant) = 6.626 × 10⁻³⁴ m² kg/s

Me of electron = 9.109 × 10 ⁻³¹ kg

speed of light = 3.0 × 10 ⁸ m/s

a) the Ek ( kinetic energy of the dislodged electron) = 0.5 mu²

Ek = 0.5 × 9.109 × 10⁻³¹ × ( 6.40 × 10⁵ )² = 1.866 × 10 ⁻¹⁹ J

b) Φ ( minimum energy needed to dislodge the electron ) can be calculated by this formula

hv =   Φ + Ek

where Ek = 1.866 × 10 ⁻¹⁹ J

v ( threshold frequency ) = c / λ where c is the speed of light and λ is the wavelength of light = 358.1 nm = 3.581 × 10⁻⁷ m

v = ( 3.0 × 10 ⁸ m/s ) / (3.581 × 10⁻⁷ m ) = 8.378 × 10¹⁴ s⁻¹

hv = 6.626 × 10⁻³⁴ m² kg/s ×  8.378 × 10¹⁴ s⁻¹ = 5.551 × 10⁻¹⁹ J

5.551 × 10⁻¹⁹ J = 1.866 × 10 ⁻¹⁹ J + Φ

Φ = 5.551 × 10⁻¹⁹ J - 1.866 × 10 ⁻¹⁹ J = 3.685 × 10⁻¹⁹ J

7 0
2 years ago
Lewis structure for carbon tetrabromide (CBrÁ), in which a central carbon atom is bound to four atoms of the group 7A element br
nlexa [21]
Remember that carbon has 4 electrons in its valence shell meanwhile bromine has 7

So i think the lewis structure would be :

Br

C       Br      Br  

Br

Hope this helps

7 0
3 years ago
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