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3 years ago

What clues are useful in reconstructing pangaea

2 answers:

6 0

You can use map and notice one thinh. If you flipp over the edges of continents and put them together, you will get a big single continent that is called pangaea. Practically it's impossible but it could be imagined.

n200080 [17]3 years ago

6 0

Clues that are useful in reconstructing pangaea are the edges of the continents, glacial deposits, matching folded mountains, fossils found by scientist

<h3>Further explanation </h3>

Pangea is a supercontinent that existed during the late Paleozoic and early Mesozoic eras. Pangea assembled from earlier continental units approximately 335 million years ago, and it begin to break apart about 175 million years ago.

Clues that are useful in reconstructing pangaea are:

Fossils found by scientist: Fossils of the same plant and animal species on some of the continents that the oceans separate.
Matching folded mountains: If the continents were joined back, we can notice how the mountains match since they share, for example the same rocks sample
Glacial Deposits: Some places have glacial deposits but the temperatures are not cold to have glaciers.
Edge of Continents: The edges of the continents are useful in reconstructing Pangaea. Some continents such as South America and Africa fit each other if joined together like. Aside from the fitting of edges of the continents, the evidence presence are found in the same continents made the reconstruction easier.

<h3>Learn more</h3>

Learn more about reconstructing pangaea brainly.com/question/5959094
Learn more about Fossils brainly.com/question/6454167
Learn more about Glacial Deposits brainly.com/question/5632616

<h3>Answer details</h3>

Grade: 9

Subject: physics

Chapter: reconstructing pangaea

Keywords: Fossils, reconstructing pangaea, pangaea, clues, scientist

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3 years ago

Two stationary positive point charges, charge 1 of magnitude 3.90 nC and charge 2 of magnitude 1.80 nC, are separated by a dista

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Answer:

$v = 7793150 m/s$

Explanation:

First, we are going to calculate the electrical potential in the point middle between the two charges

Remember that the electrical potential can be calculated as:

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Where $k = 8.9874 x 10^{9} \frac{Nm^{2} }{C^{2} }$

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3 years ago

A 5.0-kg rock and a 3.0 × 10−4-kg pebble are held near the surface of the earth.(a)Determine the magnitude of the gravitational

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Answer:

a). Determine the magnitude of the gravitational force exerted on each by the earth.

Rock: $F = 49.06N$

Pebble: $F = 29.44N$

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Pebble: $a =9.8m/s^{2}$

Explanation:

The universal law of gravitation is defined as:

$F = G\frac{m1m2}{r^{2}}$ (1)

Where G is the gravitational constant, m1 and m2 are the masses of the two objects and r is the distance between them.

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<em>Case for the pebble </em> $m = 3.0 Kg$ <em>:</em>

$F = (6.67x10^{-11}kg.m/s^{2}.m^{2}/kg^{2})\frac{(5.972x10^{24} Kg)(3.0 Kg)}{(6371000 m)^{2}}$

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$a =\frac{F}{m}$

$a =\frac{(29.44 Kg.m/s^{2})}{(3.0 Kg)}$

$a =9.8m/s^{2}$

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plates.

d is the distance between the halfway.

So we can use the above formula to calculate the electric field.

V=Ed from this E=V/d substitute the values from the given equation.

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