The concepts used to solve this problem are those related to the Pythagorean theorem for which we will calculate the distance and the pitch.
According to the attached diagram we have that the expression of the resulting displacement is
Therefore the resultant displacement of the girl is
Therefore the girl has displaced around of 5 blocks
Answer:
Initial velocity, U = 28.73m/s
Explanation:
Given the following data;
Final velocity, V = 35m/s
Acceleration, a = 5m/s²
Distance, S = 40m
To find the initial velocity (U), we would use the third equation of motion.
V² = U² + 2aS
Where;
V represents the final velocity measured in meter per seconds.
U represents the initial velocity measured in meter per seconds.
a represents acceleration measured in meters per seconds square.
S represents the displacement measured in meters.
Substituting into the equation, we have;
35² = U + 2*5*40
1225 = U² + 400
U² = 1225 - 400
U² = 825
Taking the square root of both sides, we have;
Initial velocity, U = 28.73m/s
Answer:
Explanation:
The force of friction between the quails feet and the ground is:
So the coefficient of static is solve
