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anzhelika [568]

3 years ago

5

An amusement park ride spins you around in a circle of radius 2.5 m with a speed of 8.5 m/s. If your mass is 75 kg, what is the

centripetal force acting on you? A. 1530 N B. 2168 N C. 255 N D. 2359 N

2 answers:

nataly862011 [7]3 years ago

8 0

B is the correct answer - APEX

zhannawk [14.2K]3 years ago

3 0

B is the answer to this truly did the math

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A ball is thrown with an initial speed vi at an angle i with the horizontal. The horizontal range of the ball is R, and the ball

adell [148]

Answer:

Part a)

$T = 2\sqrt{\frac{R}{3g}}$

Part b)

$v_x = \frac{\sqrt{3Rg}}{2}$

Part c)

$v_y = \sqrt{Rg/3}$

Part d)

$v = \frac{1}{2}\sqrt{13Rg}$

Part e)

$\theta_i = 33.7 degree$

Part f)

$H = \frac{13R}{8}$

Part g)

$X = \frac{13R}{4}$

Explanation:

Initial speed of the launch is given as

initial speed = $v_i$

angle = $\theta_i$ degree

Now the two components of the velocity

$v_x = v_i cos\theta_i$

similarly we have

$v_y = v_i sin\theta_i$

Part a)

Now we know that horizontal range is given as

$R = \frac{v_i^2 (2sin\theta_icos\theta_i)}{g}$

maximum height is given as

$H = \frac{R}{6} = \frac{v_i^2 sin^2\theta_i}{2g}$

so we have

$v_i sin\theta = \sqrt{Rg/3}$

time of flight is given as

$T = \frac{2v_isin\theta_i}{g}$

$T = \frac{2\sqrt{Rg/3}}{g}$

$T = 2\sqrt{\frac{R}{3g}}$

Part b)

Now the speed of the ball in x direction is always constant

so at the peak of its path the speed of the ball is given as

$R = v_x T$

$R = v_x 2\sqrt{\frac{R}{3g}}$

$v_x = \frac{\sqrt{3Rg}}{2}$

Part c)

Initial vertical velocity is given as

$v_y = v_i sin\theta_i$

$v_i sin\theta = \sqrt{Rg/3}$

Part d)

Initial speed is given as

$v = \sqrt{v_x^2 + v_y^2}$

so we will have

$v = \sqrt{Rg/3 + 3Rg/4}$

$v = \frac{1}{2}\sqrt{13Rg}$

Part e)

Angle of projection is given as

$tan\theta_i = \frac{v_y}{v_x}$

$tan\theta_i = \frac{\sqrt{Rg/3}}{\sqrt{3Rg}/2}$

$\theta_i = 33.7 degree$

Part f)

If we throw at same speed so that it reach maximum height

then the height will be given as

$H = \frac{v^2}{2g}$

$H = \frac{13R}{8}$

Part g)

For maximum range the angle should be 45 degree

so maximum range is

$X = \frac{v^2}{g}$

$X = \frac{13R}{4}$

3 0

3 years ago

What is a SIMPLE way to define the law of conservation of energy? must be simple:)

saw5 [17]

Answer: The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another.

Explanation:

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3 years ago

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Which of the following materials used by plants to make food can be found in the air?

Rashid [163]

Answer:

<em><u>number</u></em><em><u> </u></em><em><u>d</u></em>

Explanation:

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A device that has the capacity to receive and store electrical energy is a(n) <br> .

Dmitriy789 [7]

A capacitor is used to receive and store electrical energy.

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In an atom is the number of protons greater, less than or equal to the number of electrons?

Igoryamba

Answer:

<em>The number of electrons and protons are always equal in a neutral atom. The total number of protons in the nucleus of an atom gives us the atomic number of that atom.</em>

Explanation:

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<em> $kai6417$ </em>

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3 years ago