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zmey [24]
2 years ago
14

Enter an expression, in terms of defined quantities and g, for the force that the scale under left pillar shows

Physics
1 answer:
ella [17]2 years ago
5 0

The expression, in terms of defined quantities and g is therefore Fu =((mg/2) +2 mp) g

<h3>What is a Scale?</h3>

This can be defined as a balance or any of various other instruments or devices for weighing.

The expression in terms of defined quantities and g, for the force that the scale under left pillar shows that Fu =((mg/2) +2 mp) g .

Read more about Force here brainly.com/question/4515354

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How much force will it take to lift a 54n object if it is on a lever that is 19m long on the side the object is on while i push
avanturin [10]

Answer:

How long will it take to travel a distance of 96 km? Givens. Solving For ... An object accelerates 3.0 m/s2 when a force of 6.0 Newtons is applied to it.

Explanation:

6 0
3 years ago
How to convert 45.77 cubic inches to cubic centimeters
Paha777 [63]
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6 0
3 years ago
Calculate the energy per photon and the energy per mole of photons for radiation of wavelength (a) 200 nm (ultraviolet), (b) 150
VMariaS [17]

Answer: a. E =9.9*EXP(-19)J

1 mole E= 596178J

b. E= 1.32*EXP(-15)J, 1 mole E=795MegaJ

c. E= 1.98*EXP(-23)J

1 mole E = 11.9J

Explanation: The Energy of a photon E, the wavelength are related by

E= h*c/wavelength

h is the Planck's constant 6.6*EXP(-34)J.s

c is speed of light 3*EXP(8)m/s

h*c=1.98*EXP(-25)

Now let's solve

a. E = h*c/wavelength

= h*c/(200*EXP(-9)m

=9.9*EXP(-19)J

1 mole of a photon contian 6.022*EXP(23)photons by advogadro

Now to get the energy of 1 mole of the photon we have

9.9*EXP(-19)*6.023*EXP(23)

=596178J

b. E=h*c/150*EXP(-12)m

=1.32*EXP(-15)J

1 mole will have

1.32*EXP(-15)*6.022*EXP(23)J

=795*EXP(6)J

c. E= h*c/1*EXP(-2)m

=1.98*EXP(-23)J

1 mole of the photon will have

1.98*EXP(-23)J *6.022*EXP(23)

= 11.9J.

You will notice that the longer the wavelength of the photon the lesser the Energy it as.

NOTE: EXP represent 10^

8 0
4 years ago
A Plane has a takeoff speed of 150 m/s and requires 1500m to reach that speed. Determine the acceleration of the plane and the t
mars1129 [50]

<u>Answer:</u>

The acceleration of the plane and the time required to reach this speed is  (a)= 7.5 m/sec^2 and time(t) = 20 seconds  

<u>Explanation: </u>

Given data Initial velocity (V_i) = 0  

Final velocity (V_f) = 150 m/second

Distance (d) = 1500 m

We have the formula,  $\mathrm{V}_{\mathrm{f}}^{2}=\mathrm{V}_{\mathrm{i}}^{2}+2 \mathrm{ad}$

which gives 150^2 = 0+2a(1500)    

22500 = 3000 a  

acceleration (a) = 7.5 m/s^2

$\mathrm{V}_{\mathrm{f}}=\mathrm{V}_{\mathrm{i}}+\mathrm{at}$

150 = 7.5 t

t= 150/7.5 = 20

t = 20 seconds.  

5 0
3 years ago
A 68 kg deer has a momentum of 952 kg∙m/s. What is its velocity?
Gwar [14]

All we need to do is divide the momentum and weight to find the velocity:

v = m / w

Solve using the values we are given.

v = 952/68 = 14 m/s

Best of Luck!

5 0
3 years ago
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