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3 years ago

What upward gravitational force does a 5600kg elephant exert on the earth?

2 answers:

8 0

Force is determined by multiplying mass and gravity (F= mg). To determine the answer, the mass of the elephant (5600 kg) is multiplied with the gravity (9.8 m/s²). The answer is 5800 N. This is the upward gravitational force that the elephant exerts on the earth.

Inessa [10]3 years ago

6 0

<u>Answer</u>

54,880 N

<u>Explanation</u>

The Gravitational force is the force exited by an object towards the center of the earth. It is called the weight of an object. The Newton's 2nd law of motion says that for every action there is equal and opposite reaction. So, if the elephant exerts a force on the earth, the earth exerts an equal force to the elephant.

Weight = mass × gravity

= 5600 × 9.8

= 54,880 N

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A car of mass of 1000 ks in accelerating at 2 ms. What resultant force acts on the car? If the

Debora [2.8K]

Answer:

Explanation:

Opp

7 0

3 years ago

wo plates with area 6.00×10−3 m2 are separated by a distance of 1.50×10−4 m . If a charge of 5.40×10−8 C is moved from one plate

liq [111]

Answer:

V = 152.542 volts

Explanation:

Given data:

area of plates $6.00\times 10^{-3} m^2$

distance between the plates is $1.50\times 10^{-4} m$

charge = $5.40\times 10^{-8} c$

we know that capacitance is given as

$C = \frac{\epsilon A}{d}$

$C = \frac{8.85\times 10^{-12} 6\times 10^{-3}}{1.50\times 10^{-4}}$

$C = 3.54\times 10^{-10} F$

potential difference is given as

$V =\frac{Q}{C} = \frac{5.40\times 10^{-8}}{3.54\times 10^{-10}}$

V = 152.542 volts

3 0

3 years ago

In a photoelectric experiment, a metal is irradiated with light of energy 3.56 eV. If a stopping potential of 1.10 V is required

konstantin123 [22]

Answer:

2.46 eV

Explanation:

It is given that,

The energy of light that fall on the metal = 3.56 eV

The stopping potential of the metal = 1.1 V

We need to find the work function of the metal. It is given by the relation as follows :

W = E-KE ...(1)

Where KE is the kinetic energy of the ejected electron and it is given by :

KE = V×e

= 1.1 eV

Put all the values in formula (1)

W = 3.56 eV - 1.1 eV

= 2.46 eV

Hence, the work function of the metal is 2.46 eV. Hence, the correct option is (c).

5 0

3 years ago

As a dilligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.39-m-

grin007 [14]

Answer:

The strength of magnetic field is $6.21 \times 10^{-5}$ T

Explanation:

Given:

Length of rod $l = 1.39$ m

Velocity $v = 3.37$ $\frac{m}{s}$

Induced emf $= 0.291 \times 10^{-3}$ V

According to the faraday's law

Induced emf = $Blv$

We have to find strength of the magnetic field,

$B = \frac{0.291 \times 10^{-3} }{1.39 \times3.37}$

$B = 6.21 \times 10^{-5}$ T

Therefore, the strength of magnetic field is $6.21 \times 10^{-5}$ T

7 0

3 years ago

What would be the best example of a fine motor skill? a. Climbing to the top of a large hill b. Feeding yourself with a spoon c.

Elden [556K]

Answer:

The correct answer is

b. Feeding yourself with a spoon

Explanation:

There are two categories of motor skills, fine motor skills and gross motor skills

Fine motorskills also known as dexterity is the synchronized use of small muscles like muscles in the wrists, hands and fingers along with the eyes. Fine motor skills are used for tasks like turning pages or using the computer key board that requires coordinated and precise movements. Human dexterity is reflected in the level of complexity of functions controlled by the nervous system.

Example of fine motor skill is Feeding yourself with a spoon while gross motor skill includes climbing to the top of a large hill spoon, running in a race and crawling

4 0

3 years ago