Explanation:
Area=1.5(1.5)=2.25m^2
Force of gravity=10N
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}
⟼Pressure=
Area
Force
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}
⟼Pressure=
2.25
10
\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}
⟼Pressure=4.4Pa
Answer:
The kinetic energy of the merry-goround after 3.62 s is 544J
Explanation:
Given :
Weight w = 745 N
Radius r = 1.45 m
Force = 56.3 N
To Find:
The kinetic energy of the merry-go round after 3.62 = ?
Solution:
Step 1: Finding the Mass of merry-go-round
m = 76.02 kg
Step 2: Finding the Moment of Inertia of solid cylinder
Moment of Inertia of solid cylinder I =
Substituting the values
Moment of Inertia of solid cylinder I
=>
=> 
=> 
Step 3: Finding the Torque applied T
Torque applied T = 
Substituting the values
T = 
T = 81.635 N.m
Step 4: Finding the Angular acceleration
Angular acceleration ,
Substituting the values,
Step 4: Finding the Final angular velocity
Final angular velocity ,
Substituting the values,
Now KE (100% rotational) after 3.62s is:
KE = 
KE =
KE = 544J
Answer:
Seven.
Explanation:
A period is a horizontal row of the periodic table. There are seven periods in the periodic table, with each one beginning at the far left. A new period begins when a new principal energy level begins filling with electrons.
Explanation:
A lightning rod (US, AUS) If lightning hits the structure:-
It will preferentially strike the rod and be conducted to ground through a wire.
Instead of passing through the structure, where it could start a fire or cause electrocution.
The parts of a lightning protection system are air terminals (lightning rods or strike) and all of the connectors and supports to complete the system.
Answer:
(a) F = 1500 N.
(b) Ratio force to the antelepe's weight = 3.40
Explanation:
Force : This can be defined as the product of mass and the distance moved by a body. Its S.I unit is Newton. It can be represented mathematically as
F = Ma
Where F= force, M = mass (Kg) and a = Acceleration (m/s²)
Weight: This can be defined as the force on a body due to gravitation field. It is also measured in Newton (N). It can be represented mathematically as
W = Mg
Where W = weight of the body, M = mass of the body (Kg), g = Acceleration due to gravity.
(a)
F = Ma
Where M = 45kg,
a = unknown.
But we can look for acceleration Using one of the equation of motion,
v² = u² + 2gs
Where v= final velocity(m/s), u = initial velocity (m/s) g = 0 m/s, g = 9.8m/s² and s = height = 2.5m.
∴ v² = 2gs
v = √2gs = √(2×9.8×2.5)
v= √49 = 7m/s
With the force applied, the impala’s velocity must increase from 0 m/s to 7 m/s in 0.21 second
∴ a = (v-u)/t
a = (7-0)/0.21 = 7/0.21
a = 33.33 m/s².
F = 45 × 33.33 ≈ 1500
F = 1500 N.
(b)
Where F = Force = 1500 N
and W = Weight = Mg = 45 × 9.8 = 441 N
∴Ratio force to the antelepe's weight = F/W = 1500/441 = 3.40
Ratio force to the antelepe's weight = 3.40
