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3 years ago

9

Write a script to check command arguments (3 arguments maximum). Display the argument one by one. If there is no argument provid

ed, remind users about the mistake. If there is an easy way to use a loop to get all arguments, use it?a) Display the source code in an editor b) Execute your script in the terminal, and display the command and the result

Computers and Technology

1 answer:

serious [3.7K]3 years ago

7 0

Answer:-args (

if:args=true

-cont

if:args=false

-cont investigating

if:args=irrelevance

-loop restate args

)

compile exec

Explanation:

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Drag each statement to the correct location.

VMariaS [17]

Answer:

$(a)\ 222_{10} = DE_{16}$ --- True

$(b)\ D7_{16} = 11010011_2$ --- False

$(c)\ 13_{16} = 19_{10}$ --- True

Explanation:

Required

Determine if the statements are true or not.

$(a)\ 222_{10} = DE_{16}$

To do this, we convert DE from base 16 to base 10 using product rule.

So, we have:

$DE_{16} = D * 16^1 + E * 16^0$

In hexadecimal.

$D =13 \\E = 14$

So, we have:

$DE_{16} = 13 * 16^1 + 14 * 16^0$

$DE_{16} = 222_{10}$

Hence:

(a) is true

$(b)\ D7_{16} = 11010011_2$

First, convert D7 to base 10 using product rule

$D7_{16} = D * 16^1 + 7 * 16^0$

$D = 13$

So, we have:

$D7_{16} = 13 * 16^1 + 7 * 16^0$

$D7_{16} = 215_{10}$

Next convert 215 to base 2, using division rule

$215 / 2 = 107 R 1$

$107/2 =53 R 1$

$53/2 =26 R1$

$26/2 = 13 R 0$

$13/2 = 6 R 1$

$6/2 = 3 R 0$

$3/2 = 1 R 1$

$1/2 = 0 R1$

Write the remainders from bottom to top.

$D7_{16} = 11010111_2$

<em>Hence (b) is false</em>

$(c)\ 13_{16} = 19_{10}$

Convert 13 to base 10 using product rule

$13_{16} = 1 * 16^1 + 3 * 16^0$

$13_{16} = 19$

Hence; (c) is true

7 0

2 years ago

Write a program that: Takes the list lotsOfNumbers and uses a loop to find the sum of all of the odd numbers in the list (hint:

Alika [10]

Answer:

Following are the code to this question:

#include <iostream>//defining header file

using namespace std;

int main()//defining main method

{

int x[]={2,3,4,6,7,8,9,1,11,12};//defining 1-D array and assign value

int i,sum=0;//defining integer variable

for(i=0;i<10;i++)//defining loop for count value

{

if(x[i]%2==1)//defining if block to check odd value

{

sum=sum+x[i];//add value in sum variable

}

}

cout<<sum;//print sum

return 0;

}

Output:

31

Explanation:

In the above-given program, an integer array "x" is declared that holds some integer values, and in the next line two integer variable "i and sum" is defined which is used to calculate the value.

In the next line, a for loop is declared, that counts all array value, and it uses the if block to check the odd value and add all the value into the sum variable.

5 0

3 years ago

Why are open standards important in the data communications industry?

IrinaK [193]

They enable interoperability between software and hardware from different vendors.

5 0

3 years ago

You can place an insertion point by clicking in the field or by pressing ____.

Slav-nsk [51]

You can place an insertion point by clicking in the field or by clicking F2 keyboard shortcut. Insertion point is usually characterized by a blinking vertical line that allows you to insert a next character that you wanted.

4 0

3 years ago

This is your code.

lubasha [3.4K]

Answer:

35

Explanation:

We will be going inside B array, because he was in second place in array E,and will be the first element of array B, so it's 35

E can be understanded as:

E=[[21, 'dog', 'red'],[35, 'cat', 'blue'],[12, 'fish', 'green']], so, you can see array E as array of arrays or so-called two-dimensional array

6 0

2 years ago