Answer:
A. 1.75mol of CO2
B. 120g of urea
C. 72g of water
Explanation:
The balanced equation for the reaction is given below:
CO2+ 2NH3 --> H2NCONH2 + H2O
A. From the balanced equation,
1mole of CO2 requires 2moles of NH3.
Therefore, Xmol of CO2 will require 3.5moles of NH3 ie
Xmol of CO2 = 3.5/2 = 1.75mol
B. Let us calculate their molar mass
MM of H2NCONH2 = (2x1)+14+12+16+14+(2x1) = 60g/mol
MM of NH3 = 14 +(3x1) = 17g/mol
But from the balanced equation, 2 moles of NH3 was required. Therefore the mass conc. of NH3 = 2 x 17 = 34g.
Now we calculate the mass of urea produced as follows:
From the equation,
34g of NH3 was required to produce 60g of urea.
Therefore, 68g of NH3 will produce Xg of urea i.e
Xg of urea = (68x60)/34 = 120g
C. From the balanced equation,
2moles of NH3 was required to produced 1mole of H2O.
Therefore, 8 moles of NH3 will produce Xmol of water ie
Xmol of H2O = 8/2 = 4moles
Converting this mole(4moles of water to grams), we have:
MM of H2O = (2x1)+ 16 = 18g/mol
Mass conc. of H20 = 4 x 18 = 72g
