All categories

3 years ago

How would you describe the motion of plates in a divergent boundary?

1 answer:

Nutka1998 [239]3 years ago

3 0

Divergent boundaries occur along spreading centers where plates are moving apart and new crust is created by magma pushing up from the mantle. Picture two giant conveyor belts, facing each other but slowly moving in opposite directions as they transport newly formed oceanic crust away from the ridge crest.

You might be interested in

The green pigment required for photosynthesis is:

katen-ka-za [31]

C. chlorophyll

gc sh jj cd dhjjfddr

7 0

3 years ago

How many molecules of O2 will be required to produce 28.8 g of water?

Mrac [35]

I think 1.67 x 10^20

5 0

3 years ago

What part of an Atom undergoes change during radioactive decay

Aloiza [94]

It is clear that the core is subject to change

7 0

3 years ago

How many grams of lead(II) sulfate (303 g/mol) are needed to react with sodium chromate (162 g/mol) in order to produce 0.162 kg

Afina-wow [57]

Answer : The mass of $PbSO_4$ needed are, 1.515 grams.

Explanation :

First we have to calculate the mole of $PbCrO_4$ .

$\text{Moles of }PbCrO_4=\frac{\text{Mass of }PbCrO_4}{\text{Molar mass of }PbCrO_4}=\frac{0.162g}{323g/mole}=0.005mole$

Now we have to calculate the moles of $PbSO_4$ .

The balanced chemical reaction will be,

$PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4$ produced from 1 mole of $PbSO_4$

So, 0.005 mole of $PbCrO_4$ produced from 0.005 mole of $PbSO_4$

Now we have to calculate the mass of $PbSO_4$

$\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4$

$\text{Mass of }PbSO_4=0.005mole\times 303g/mole=1.515g$

Therefore, the mass of $PbSO_4$ needed are, 1.515 grams.

6 0

3 years ago

Calculate the density of helium if a balloon with a capacity of 5.00 L holds 0.890 g.

liubo4ka [24]

Answer:

Explanation:

Density is m/V. Also, 1 liter = 1000 $cm^3$ . So, we get 0.890/(5*1000) = $1.78*10^{-4}$ g/cm^3. You can convert this to kg/m^3 as well by multiplying it by 10. Depends which one you want.

5 0

3 years ago