Answer:
ok 3 = 9 15 i got 15 so what
Explanation:
Answer:
The warmer, lighter air rises, bringing cooler, heavier air to low altitudes.
Air at higher altitudes doesn't have as much air weighing down on it from above.
Explanation:
In short - air pressure is the result of the cumulative force that air molecules act on objects below them due to Earth's gravity. The higher the altitude, the less air molecules there are to act a force below them, and therefore, there's less air pressure at higher altitudes.
Benzene is the simplest example of the aromatic compound
Firstly, we want to explain what is the meaning of aromaticity?
the aromaticity is called on any compound which has cyclic shape and has a resonance. Resonance is delocalization of the electrons (which form the double bond) in the molecules, in other words, the double bond moves through the compound by the movement of electrons which leads to increasing the stability of the compound by this process which called resonance. The resonance may occur in open or cyclic compounds, and if it occurs in cyclic compounds, these compounds are called aromatic compounds. So, the benzene considered to be the simplest aromatic compound where it is not only has a resonance in a cyclic ring but also it was the first aromatic compound discovered and also, the most common aromatic compounds are derivatives of it (benzene).
Answer:
39.6 mL
Explanation:
Step 1: Write the balanced neutralization reaction
Ba(OH)₂(aq) + 2 CH₃COOH(aq) ⟶ Ba(CH₃COO)₂(aq) + 2 H₂O(l)
Step 2: Calculate the moles corresponding to 2.78 g of CH₃COOH
The molar mass of CH₃COOH is 60.05 g/mol.
2.78 g × 1 mol/60.05 g = 0.0463 mol
Step 3: Calculate the moles of Ba(OH)₂ needed to react with 0.0463 moles of CH₃COOH
The molar ratio of Ba(OH)₂ to CH₃COOH is 1:2. The moles of Ba(OH)₂ needed are 1/2 × 0.0463 mol = 0.0232 mol.
Step 4: Calculate the volume of 0.586 M solution that contains 0.0232 moles of Ba(OH)₂
0.0232 mol × 1 L/0.586 mol = 0.0396 L = 39.6 mL
