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3 years ago

Cylinder with a mass of 12g has a radius measuring 2cm and height of 6cm what is its density

Chemistry

1 answer:

lakkis [162]3 years ago

8 0

Answer:

Given:

m = 12 g, the mass of the cylinder

r = 2 cm, the radius of the cylinder

h = 6 cm, the height of the cylinder.

Calculate the volume, V, of the cylinder.

V = πr²h

= π*(2 cm)²*(6 cm)

= 75.398 cm³

By definition,

density = mass/volume.

Therefore,

density = m/V

= (12 g)/(75.398 cm³)

= 0.159 g/cm³

= 0.16 g/cm³ (nearest hundredth)

Answer: 0.16 g/cm³

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A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the

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A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

<h3>What is Combined Gas Law ?</h3>

This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.

It is expressed as

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

where,

P₁ = first pressure

P₂ = second pressure

V₁ = first volume

V₂ = second volume

T₁ = first temperature

T₂ = second temperature

Now put the values in above expression we get

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

$\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}$

$P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}$

P₂ = 1.76 atm

Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

Learn more about the Combined gas Law here: brainly.com/question/13538773

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