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AlexFokin [52]
3 years ago
10

Lead has a density of 11.3 g/mL. If you have 105 grams of lead,

Chemistry
1 answer:
Elza [17]3 years ago
6 0

Answer:

<h2>Volume = 9.29 mL</h2>

Explanation:

Density of a substance can be found by using the formula

Density( \rho) =  \frac{mass}{volume}

From the question

Density = 11.3 g/mL

mass = 105 g

Substitute the values into the above formula and solve for the volume

That's

11.3 =  \frac{105}{v}

Cross multiply

11.3v = 105

Divide both sides by 11.3

v =  \frac{105}{11.3}

v = 9.29203

We have the final answer as

<h3>Volume = 9.29 mL</h3>

Hope this helps you

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Calculate the average velocity of nitogen molecule at STP<br>​
JulijaS [17]

Answer:

Nitrogen molecule is 28 neuclons×1.67×10-27 kg/nucleon = 4.68 д 10-26 kg. So the average speed of a gas molecule is about 500 m/sec. This is roughly the speed of sound in a gas 340 m/sec. So the average kinetic energy of the gas molecules is related to the temperature of the gas.

I hope this is helpful

4 0
3 years ago
Some growth regulators are useful to farmers and gardeners.<br> O True<br> O False
lisov135 [29]

Answer:

True

Explanation:

The first artificial use of a PGR was to stimulate the production of flowers on pineapple plants. They are now used widely in agriculture. Plant hormones are also used in turf management to reduce the need to mow, to suppress seedheads, and to suppress other types of grass.

3 0
3 years ago
The ksp value for lead(ii chloride is 2.4 × 10?4. what is the molar solubility of lead(ii chloride?
charle [14.2K]
Molar solubility is number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated. 

The molar solubility of lead(ii) chloride with ksp value of 2.4 × 10e4 can be solve as: 

Ksp = s2 = 2.4 × 10e4
s2 = 2.4 × 10e4
s = √(2.4 × 10e4)
s =  154.9 mol/L
6 0
3 years ago
What piece of lab equipment would you use to conduct a small chemical experiment?
Scrat [10]

test tube

Explanation:

you state it is small and a test tube is the smallest container out of the answers you listed

6 0
3 years ago
Read 2 more answers
14. Calculate the mass in grams of oxygen required to react completly with 0.75 moles of Aluminum.
cluponka [151]
  • 3mols of O_2 react with 4mol of Al
  • 3/4=0.75mol O_2 react with 1mol of Al

Moles of O_2:-

  • 0.75(0.75)
  • 0.5625mol

Mass of O_2:-

  • moles(Molar mass)
  • 0.5625(32)
  • 18g

Option B

8 0
2 years ago
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