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Sav [38]
2 years ago
8

Roman paid $150 to join a handball club. He pays an additional $15 every time he uses one of the club's handball courts. Write a

n equation that describes Roman's total cost for playing handball as a function of the number of times he plays. Let C = the total cost and n = the number of times he plays
Mathematics
2 answers:
Alekssandra [29.7K]2 years ago
4 0

Answer:

mmmmmmmmmmmmmmmmmmmm

Step-by-step explanation:

brilliants [131]2 years ago
3 0
C = 15n + 150 I think
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Find the Area of a circle with a diameter of 10 inches
LekaFEV [45]

Answer:

78.5 inch²

Step-by-step explanation:

Given

diameter (d) = 10 inches

radius (r) = 10 / 2 = 5 inches

Area of circle

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= 3.14 * ( 5)²

= 3.14 * 25

= 78.5 inch²

6 0
2 years ago
_______ will produce a rational answer when multiplied by 0.9
harkovskaia [24]

Answer:

10

Step-by-step explanation:

A rational number is 9.

When you multiply 0.9x10 you get the sum of 9.

9 is a rational number because it is a perfect square and an integer.

I hope this helps you understand :)

4 0
3 years ago
Read 2 more answers
Line AB contains points A ( -3,5) and B (-3,3). Line AB has a slope that is
Alex_Xolod [135]

Answer:

slope  that is undefined

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

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m = \frac{3-5}{-3+3} = \frac{-2}{0}

Division by zero is undefined

Thus the slope of AB is undefined

7 0
2 years ago
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Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?
Yanka [14]

Answer:

Step-by-step explanation:

\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.

\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\

(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+  \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.

8 0
1 year ago
Which value of a in the exponential function below would cause the function to stretch?
lesya692 [45]

Answer:

51251552 | \sqrt[ { {).5644}^{2} }^{25} ]{051} |

hhkhgguiffhkjgilkgfgkhff

8 0
3 years ago
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