The condition for maximum intensity is the same as that for a double slit. However, angular separation of the maxima is generally much greater because the slit spacing is so small for a diffraction grating. For a diffraction grating with lines/mm = lines/inch, the slit separation is d = micrometers = x10^ m.
<span>The electric field is inversely proportional to the distance.</span>
Answer:
Avg.velocity=(Δy/ Δt) =(net displacement/ total time for journey)
Δy = 0
Δt = t
so avg. velocity = 0/t =0
Avg. speed =(total distance traveled/ total time for journey)
total distance = up +down = Ymax+Ymax= 2 Ymax
total time = t
avg. speed = 2 Ymax/t
Explanation:
Since there is no net displacement from the original position,velocity is zero. Claudia is right!
while it covered some distance in time t so its speed is not as qouted by Hossien
Answer:
F = 1.68 N
Explanation:
Let's solve this exercise in parts.
Let's use the concept of conservation of the mechanical nerve
initial
Em₀ = 500 J
The energy is totally kinetic
Em₀ = K = ½ m v₀²
v₀ = 
v₀ = √ (2 500/32)
v₀ = 5.59 m / s
now with kinematics we can find a space
v² = v₀² - 2 a x
the negative sign is because the body is stopping
a =
let's calculate
a = (5.59² - 5.1²) / 2 50
a = 0.0524 m / s²
Finally let's use Newton's second law
F = ma
F = 32 0.0524
F = 1.68 N
