Answer:
q = 0.036 C
Explanation:
Given that,
Current passes through a defibrillator, I = 18 A
Time, t = 2 ms
We need to find the charge moved during this time. We know that,
Electric current = charge/time

Put all the values,

So, 0.036 C of charge moves during this time.
It is electrical energy into connected energy has in relation to the question
Answer:
50.4÷1.18= 42.7m/s as speed is equal to the distance over the time taken
Answer:
Hydrated iron(III) oxide, or ferric oxide
Explanation: