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poizon [28]
3 years ago
13

Define the refraction index of a

Physics
1 answer:
Andrews [41]3 years ago
6 0

Answer:

see below

Explanation:

refractive index of a medium is defined as the ratio of the speed of light in vacuum to the speed of light in medium

critical angle of glass is 42 means that if the angle of incidence inside the glass is 42 degrees, then the angle of refraction in the optically less dense medium will be 90 degrees

hope this helps

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Distance and ___ are really the same quantity. A. length b. direction c. speed d. displacement​
Oksi-84 [34.3K]

Answer:

distance and length are the same quantity

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3 years ago
Assume that each cubic centimeter of water has a mass of exactly 1.00 g. what is the mass of one cubic meter of water in kilogra
statuscvo [17]

The mass of one cubic meter of water in kilograms is 1 kg.

This is a conversions case. First, we must determine how many cubic centimeters there are in a cubic meter. We have 1000 of these after conversion.

This essentially indicates that 1000 units of water, each with a volume of one cubic centimeter, would have to combine before we could create a cubic meter of water.

Knowing that one cubic centimeter weighs one gram, 1000 cubic centimeters would weigh 1000 * 1, or 1000g, or one kilogram.

Thus, 1 cubic meters of water will weigh 1 * 1000g = 1000g, or just 1 kg.

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4 0
1 year ago
A 50 kg car is pushed so that it speeds up from 20 m/s to 50 m/s in 3 seconds. What is the force acting on the car?
egoroff_w [7]

Answer:

A. 500 N

Explanation:

Acceleration is change in velocity over change in time.

a = Δv / Δt

a = (50 m/s − 20 m/s) / 3 s

a = 10 m/s²

Force is mass times acceleration.

F = ma

F = (50 kg) (10 m/s²)

F = 500 N

3 0
3 years ago
A stack of 1500 bricks covers a ground area of 2.750m by 1.350m.the average mass of bricks is 3.200kg.calculate the total force
lozanna [386]

The total force on the ground due to the bricks is 47,040 N.

<h3>Total force on the ground</h3>

The total force on the ground due to weight of the bricks is calculated as follows;

Fₙ = mg

where;

  • Fₙ is normal force
  • m is mass of the brickes
  • g is acceleration due to gravity

Fₙ = (1500 x 3.2) x 9.8

Fₙ = 47,040 N

Thus, the total force on the ground due to the bricks is 47,040 N.

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5 0
2 years ago
A sled is initially given a shove up a frictionless 37.0 ∘ incline. It reaches a maximum vertical height 1.20 m higher than wher
labwork [276]

The initial speed of the sled at the given height is 4.85 m/s.

<h3>Initial speed of the sled</h3>

Apply the principle of conservation of energy;

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

  • h is the vertical height reached
  • g is acceleration due to gravity

v = √(2 x 9.8 x 1.2)

v = 4.85 m/s

Thus, the initial speed of the sled at the given height is 4.85 m/s.

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5 0
2 years ago
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