Answer:
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Explanation:
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The change in energy after the collision is <u>0.5</u>
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<h3>What is change in energy?</h3>
This refers to the difference in the energy where energy is the capacity to do work. There different forms of energy they include mechanical energy, solar energy, electrical energy and so on.
The energy described in the problem is mechanical energy and it is of two types kinetic energy and potential energy
<h3>solving for the change in energy as a result of the collision</h3>
where mass of particle mp = 4 kg
mass of object mb = 6 kg
force constant of spring k = 100 N/m
amplitude A = 2 m
kinetic energy = 1/2 mv^2
initial velocity u = Aω
ω = sqrt ( 100/ 4 )
u = 2 sqrt ( 100/ 4 )
u = 10m/s
final velocity v = 5 m/s
change in energy
= - 0.5 * ( 4 + 4 ) * 5^2 + 0.5 * 4 * 10^2 ) / 0.5 * 4 * 10^2
= 0.5
Read more on change in energy here: brainly.com/question/26066414
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Given:
initial angular speed, 
= 21.5 rad/s
final angular speed, 
= 28.0 rad/s
time, t = 3.50 s
Solution:
Angular acceleration can be defined as the time rate of change of angular velocity and is given by:
Now, putting the given values in the above formula:
Therefore, angular acceleration is:
Answer:
0.739
Explanation:
If we treat the four tire as single body then
W ( weight of the tyre ) = mass × acceleration due to gravity (g)
the body has a tangential acceleration = dv/dt = 5.22 m/s², also the body has centripetal acceleration to the center = v² / r
where v is speed 25.6 m/s and r is the radius of the circle
centripetal acceleration = (25.6 m/s)² / 130 = 5.041 m/s²
net acceleration of the body = √ (tangential acceleration² + centripetal acceleration²) = √ (5.22² + 5.041²) = 7.2567 m/s²
coefficient of static friction between the tires and the road = frictional force / force of normal
frictional force = m × net acceleration / m×g
where force of normal = weight of the body in opposite direction
coefficient of static friction = (7.2567 × m) / (9.81 × m)
coefficient of static friction = 0.739
Answer:
<em>1.49 x </em>
<em></em>
<em></em>
Explanation:
Kepler's third law states that <em>The square of the orbital period of a planet is directly proportional to the cube of its orbit.</em>
Mathematically, this can be stated as
∝ 
<em>to remove the proportionality sign we introduce a constant</em>
= k
k = 
Where T is the orbital period,
and R is the orbit around the sun.
For mars,
T = 687 days
R = 2.279 x
for mars, constant k will be
k = 
= 3.987 x 
For Earth, orbital period T is 365 days, therefore
= 3.987 x x
= 3.34 x 
R =<em> 1.49 x </em><em></em>
