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damaskus [11]
3 years ago
14

Match the following.

Chemistry
1 answer:
Andru [333]3 years ago
5 0

Answer: Please see below for answers

Explanation: Matching appropriate labels , we have

1)3/4 of the way to second equivalence point of a diprotic acid/strong base titration-- pH=pka₂

equivalence point of a weak base/strong acid titration=pH<7

equivalence point of a strong acid/strong base titration= pH=7

equivalence point of a weak acid/strong base titration=pH>7

half-way to equivalence point of a weak acid/strong base titration pH =pka

where

pH gives the measure of the amount of concentration of hydrogen ions in an aqueous solution.

pKa  is known as acid dissociation constant which explains the equilibrum at which a chemical species can give out or receive proton

pka₂ is the acid dissociation constant for the second ionization energy.

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What is the maximum mass of zinc oxide that can be produced by the reaction of 42.900000000000006g of zinc sulfide and 44.187000
Masja [62]

Answer:

Mass = 0.00541 g

Explanation:

We will convert the larger given values in to smaller by rounding these figures.

Given data:

Mass of zinc sulfide = 43 g

Mass of oxygen = 44.2 g

Mass of zinc oxide = ?

Solution:

Chemical equation:

2ZnS + 3O₂ → 2ZnO + 3SO₂

Number of moles of ZnS:

<em>Number of moles = mass/ molar mass </em>

Number of moles =  43 g/ 97.5 g/mol

Number of moles = 0.44 mol

Number of moles of Oxygen:

<em>Number of moles = mass/ molar mass </em>

Number of moles =  44.2 g/ 32 g/mol

Number of moles = 1.4 mol

Now we will compare the moles of oxygen and zinc sulfide with zinc oxide.

                             ZnS        :       ZnO

                                2          :          2

                              0.44       :         0.44

                              O₂          :          ZnO

                              3           :            2

                              1.4          :           2/3×1.4 =0.93

The number of moles of zinc oxide produced by ZnS are less so it will limiting reactant.

Mass of zinc oxide:

Mass = number of moles / molar mass

Mass = 0.44 mol / 81.38 g/mol

Mass = 0.00541 g

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