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Tamiku [17]
2 years ago
13

A certain man needed 400N of force to pull a load through a distance of 150cm in 8s . Calculatell i) the work done by man ii) th

e power developed by man
Chemistry
1 answer:
Igoryamba2 years ago
5 0

Answer:

a) 600 J

b) 75 W

Explanation:

Force= 400 N, distance = 150 cm = 1.5 m, time= 8s

a) Work is the product of force acting on an object and distance (or displacement). The S.I unit of work is the joules.

Work = force × distance = 400 × 1.5 = 600 J

b) Power is the amount of energy transferred per unit time. It is the ratio of work to time. The S.I unit of power is watt

Power = work/time = 600 / 8 = 75 W

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How many molecules units are in 4.5 moles of CF4
kobusy [5.1K]
1.0 mole ---------- 6.02x10²³ molecules
4.5 moles -------- ?

4.5 * 6,02x10²³ / 1.0

= 2.709x10²⁴ molecules units
7 0
3 years ago
What is the correct symbol of an ion containing 17 protons,20 neutrons and 18 electrons
Nataliya [291]

Answer:

The symbol of the ion is A^-

Explanation:

Let A be the symbol of the element.

Proton = 17

Electron = 18

Neutron = 20

Since the element has more electrons than protons, it means it has gain electrons.

From the question given,

The difference between the electron and proton = 18 — 17 = 1

So, the element has gain 1 electron.

Therefore the symbol of the ion is A^-

3 0
3 years ago
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4 0
3 years ago
Which is an example of a set point for the body? A. hair color B. type of blood C. thumb crossing style D. amount of blood gluco
Mama L [17]
The Answer Is B Type Of Blood
7 0
2 years ago
The following initial rate data are for the reaction of hypochlorite ion with iodide ion in 1M aqueous hydroxide solution: OCI+r
Vinil7 [7]

Answer:

Rate = k [OCl] [I]

Explanation:

OCI+r → or +CI

Experiment [OCI] M I(-M) Rate (M/s)2

1 3.48 x 10-3 5.05 x 10-3 1.34 x 10-3

2 3.48 x 10-3 1.01 x 10-2 2.68 x 10-3

3 6.97 x 10-3 5.05 x 10-3 2.68 x 10-3

4 6.97 x 10-3 1.01 x 10-2 5.36 x 10-3

The table above able shows how the rate of the reaction is affected by changes in concentrations of the reactants.

In experiments 1 and 3, the conc of iodine is constant, however the rate is doubled and so is the conc of OCl. This means that the reaction is in first order with OCl.

In experiments 3 and 4, the conc of OCl is constant, however the rate is doubled and so is the conc of lodine. This means that the reaction is in first order with I.

The rate law is given as;

Rate = k [OCl] [I]

5 0
2 years ago
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