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Doss [256]
3 years ago
9

How many outer electrons does cesium and magnesium have?

Chemistry
1 answer:
Tanzania [10]3 years ago
6 0
The outer electrons of an element are called the valence electrons. They help make an element stable.

Cesium : 1 valence electron<span>.

Magnesium : 2 valence electrons</span>
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How many moles in 2 h2o molecules
alexandr1967 [171]

Answer:

2 molecules of water represents 3.32 x 10^-24 moles of water.

Explanation:

To find the solution to this problem, you have to use the concept of Avogadro´s number, that is in 1 mol of any element o compound there are                    6.022 x 10^23 molecules. Then,

1 mol H2O ------------- 6.022 x 10^23 molecules

x= 3.32 x 10^-24 ---- 2 molecules.

2 molecules of water represents 3.32 x 10^-24 moles of water.

5 0
3 years ago
When a reaction occurs between atoms with ground state electron configuration 1s2 2s1 and 1s2 2s2 2p5 the predominant type of bo
fenix001 [56]

Answer: The bond formed between the elements will be ionic bond.

Explanation: We are given two elements having electronic configurations:

Element 1: 1s^22s^1

Element 2: 1s^22s^22p^5

Element 1 can easily loose 1 electron to attain stable electronic configuration and Element 2 can accept 1 electron to attain stable electronic configuration.

For these elements, there will be a complete transfer of electron from Element 1 to Element 2. Hence, this will form a ionic bond.

From the configuration, Element 1 is Lithium and Element 2 is Fluoride. So, the compound is LiF.

5 0
3 years ago
I NEED HELP PLEASE !!!!
inysia [295]

Answer:

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Explanation:

3 0
3 years ago
Read 2 more answers
What is the radius of a hydrogen atom whose electron is bound by 0.544 ev? express your answer with the appropriate units?
insens350 [35]
First, we need to calculate the principal quantum number n for this electron, using the equation:
E = (-13.60 eV) / (n x n)
where E is the energy that is used to bound the electron (here, E = - 0.544 eV).
- 0.544 eV = (-13.60 eV) / (n x n)
n x n = (- 13.60 eV) / (- 0.544 eV)
n x n = 25
n = 5

The orbital radius that is equal to the radius of a hydrogen atom is calculated using the equation:
r = 0.053 nm x n x n
r = 0.053 nm x 5 x 5
r = 0.053 nm x 25
r = 1.325 nm
6 0
3 years ago
How many atoms of magnesium metal are needed to produce 3.87 moles of magnesium oxide
Ket [755]

Answer:

48.42g of Mg

Explanation:

4 0
2 years ago
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