Given data:
Volume of HCl = 14.22 ml
Molarity of HCl = 2.97 M
mmoles of HCl = 14.22 * 2.97 = 42.2 mmoles
Volume of NaOH = 5.00 ml
Molarity of NaOH = 0.1055 M
mmoles of NaOH = 5.00 *.1055 = 0.5275 mmoles
Since HCl and NaOH combine in a 1:1 ratio
# moles of NaOH = # moles of excess HCl that is neutralized = 0.5275 moles
Now, the total moles of HCl taken = # mmoles HCl neutralized by antacid + # mmoles of excess HCl
42.2 = mmoles HCl neutralized by antacid + 0.5275
Therefore,
mmoles of HCl neutralized by antacid = 42.2 - 0.5275 = 41.6725 mmoles = 41.7 mmoles
Answer:
The atoms of different elements have different numbers of protons and electrons.
Answer:
Na2O+H2O=2NaOH
Step by step exp.
Given:
Equation Na2O+H2O=NaOH
To find: Balance the equation
Solution:
Taking LHS of the equation
LHS=Na2O+H2O
There is 2 sodium, 2 oxygen,& 2 hydrogen
To balance the equation we have equal number of atom so we multply 2 to the RHS=2NaOH
There fore the equation form is
Na2O+H2O=2NaOH
16.4 grams is the mass of solute in a 500 mL solution of 0.200 M
.
sodium phosphate
Explanation:
Given data about sodium phosphate
atomic mass of Na3PO4 = 164 grams/mole
volume of the solution = 500 ml or 0.5 litres
molarity of sodium phosphate solution = 0.200 M
The formula for molarity will be used here to know the mass dissolved in the given volume of the solution:
The formula is
molarity = 
putting the values in the equation, we get
molarity x volume = number of moles
0.200 X 0.5= number of moles
number of moles = 0.1 moles
Atomic mass x number of moles = mass
putting the values in the above equation
164 x 0.1 = 16.4 grams
16.4 grams of sodium phosphate is present in 0.5 L of the solution to make a 0.2 M solution.