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Trava [24]
2 years ago
6

Another question please help!!! :)

Chemistry
1 answer:
Oxana [17]2 years ago
6 0

The answer is [Boron]

I had this answer on my Chemistry test!

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How many protons are there in one atom of hydrogen
borishaifa [10]

Answer:

There is only one proton because it has a molecular mass of one

3 0
3 years ago
Magnesium hydroxide [Mg(OH)2] is an ingredient in some antacids. How many grams of Mg(OH)2 are needed to neutralize the acid in
Allushta [10]

Answer:

1.95g of Mg(OH)2 are needed

Explanation:

Mg(OH)2 reacts with HCl as follows:

Mg(OH)2 + 2 HCl → MgCl2 + 2H2O

<em>Where 1 mole of Mg(OH)2 reacts with 2 moles of HCl</em>

To solve this question we must find the moles of acid. Then, with the chemical equation we can find the moles of Mg(OH)2 and its mass:

<em>Moles HCl:</em>

158mL = 0.158L * (0.106mol / L) = 0.01675 moles HCl

<em>Moles Mg(OH)2:</em>

0.01675 moles HCl * (2mol Mg(OH)2 / 1mol HCl) = 0.3350 moles Mg(OH)2

<em>Mass Mg(OH)2 -Molar mass: 58.3197g/mol-</em>

0.3350 moles Mg(OH)2 * (58.3197g / mol) =

<h3>1.95g of Mg(OH)2 are needed</h3>
3 0
3 years ago
the atomic masses of 63 cu (69.17 percent) and 65 cu (30.83 percent) are 62.94 and 64.93 amu, respectively. calculate the averag
docker41 [41]

Answer:

The average atomic mass of copper is 63.55 amu.

Explanation:

hope this help

7 0
2 years ago
Read the text
Citrus2011 [14]

Answer:

1. EXPOSE TWO GROUPS TO THE AROMA OF CHOCOLATE CHIP COOKIES BAKING

2.HAVE ONE GROUP EAT ONLY CHOCOLATE CHIPS COOKIES, AND HAVE THE OTHER GROUP EAT ONLY RADISHES

3.

3 0
2 years ago
Calculate the freezing point of a 0.08500 m aqueous solution of nano3. the molal freezing-point-depression constant of water is
Citrus2011 [14]
Depression in freezing point (ΔT_{f}) = K_{f}×m×i,
where, K_{f} = cryoscopic constant = 1.86^{0} C/m,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For NaNO_{3})

Thus, (ΔT_{f}) = 1.86 X 0.0085 X 2 = 0.03162^{0}C

Now, (ΔT_{f}) = T^{0} - T
Here, T = freezing point of solution
T^{0} = freezing point of solvent = 0^{0}C
Thus, T = T^{0} - (ΔT_{f}) = -0.03162^{0}C
8 0
3 years ago
Read 2 more answers
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