Ask question

Ask question

All categories

3 years ago

12

Which statement correctly describes the conductivity of the specified material?

1 answer:

scoray [572]3 years ago

4 0

Answer:

Gold has a high conductivity

Explanation:

This is because gold is a metal that occur free in nature in rocks, alluvial , grains e.t.c. it is a transition metal and in group 11 of the periodic table do it conduct electricity. It has has conductivity because it is a metals because all metals have ability to conduct electricity. When it is pure, it is a bright, slightly reddish yellow, . It is soft, malleable.

It is a ductile metal

and ductile metal.

You might be interested in

PLEASE HELP ASAP!

LiRa [457]

Heart arteries lungs capillaries veins heart

6 0

3 years ago

Explain why some atoms gain or lose electrons to form ions.

anygoal [31]

Because some atoms<span> are more stable when they </span>gain or lose<span> an </span>electron<span> and </span>form ions<span>.</span>

7 0

3 years ago

Read 2 more answers

A 500.0 mL sample of 0.18 MHClO4 is titrated with 0.27 MCsOH. Determine the pH of the solution after the addition of 250.0 mL of

NNADVOKAT [17]

Answer:

or i go

Explanation:

i must go ooon sjsj

7 0

3 years ago

How many moles of helium are 8.84×10^24 atoms of He?

viva [34]

Answer:

14.77 mol.

Explanation:

It is known that every 1.0 mole of compound or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms.

<u><em>Using cross multiplication:</em></u>

1.0 mole of He contains → 6.022 x 10²³ atoms.

??? mole of He contains → 8.84 x 10²⁴ atoms.

<em>∴ The no. of moles of He contains (8.84 x 10²⁴ atoms) </em>= (1.0 mol)(8.84 x 10²⁴ atoms)/(6.022 x 10²³ atoms) =<em> 14.77 mol.</em>

8 0

3 years ago

What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?

mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

$C=\frac{n}{V}$ .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is $K_{2}SO_{4}$ thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass

Putting the values,

$n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol$

Thus, number of moles of $K_{2}SO_{4}$ will be $0.1061\times 0.5=0.053 mol$ .

The volume of solution is 225 mL, converting this into L,

$1 mL=10^{-3}L$

Thus,

$225 mL=0.225 L$

Putting the values in equation (1),

$C=\frac{(0.053 mol}{0.225 L}=0.236 M$

Therefore, concentration of potassium sulfate solution is 0.236 M.

4 0

3 years ago